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murzikaleks [220]
3 years ago
7

Solve the quadratic equation by factoring. check your solutions in the original equation. (enter your answers as a comma-separat

ed list.) 2x2 = 19x + 33
Mathematics
1 answer:
Scrat [10]3 years ago
3 0
2x²-19x-33=0
(2x-22 )(2x.+3 ) = 0
(x-11)(2x+3)=0
x-11=0 implies x = 11
2x+3=0 implies x = -3/2
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How do I answer this question
soldi70 [24.7K]

The answer is C. 2.

This is because the part that is inside of the parentheses is equal to 4. Multiplying the fractions in the numerator is equal to 4^\frac{3}{2}.

\frac{4^\frac{3}{2}}{4^\frac{1}{2}}=4., using the exponential rule 3/2-1/2=2/2 or 1. 4^1=4.

Now, we reduced the fraction, so all that is left is (4)^\frac{1}{2}. This is equal to 2.

So your answer is 2.

I hope this helps :)

8 0
4 years ago
Read 2 more answers
PLEASE HELP!!! I NEED THE ANSWER SOON :)
densk [106]
y=2x \newline y= x^{2} -3

Substitue 2x for y in the second equation:

2x= x^{2} -3

Rearrange to a x^{2} +bx+c=0 form:

x^{2} -2x-3=0

Factor:

(x-3)(x+1)=0

Zeros are x=3 and x=-1

To find y-coordinates of pts of intersection, plug these x-values into first equation to get y=-2 and y=6
4 0
3 years ago
You have 42 coins with a total value of $3.00. Some of the coins are dimes, and the rest are quarters.
nlexa [21]

Answer:

1. $3.00+42=$3.42

2. 4 Dimes , 2 Pennies

Step-by-step explanation:

2. 4 Dimes = 40 cents , 2 pennies = 2 cents

1. Add up 3.00+42 and that is how you could get the answer for number 1 .

6 0
3 years ago
In 1990, the cost of tuition at a large Midwestern university was $99 per credit hour. In 2003, tuition had risen to $268 per cr
vodka [1.7K]

Answer:

63%

Step-by-step explanation:

<em>From the question, we aim to find the percent increase in the tuition</em>

Given data

initial cost= $99 per credit hour

Final cost=  $268 per credit hour

% increase= (Final - initial )/initial *100

substitute

% increase= (268- 99 )/268 *100

% increase= 169 /268 *100

% increase= 0.630*100

% increase= 63%

Hence the increase in the tuition from 1990 to 2003 is 63%

5 0
3 years ago
Kent has two similar cylindrical pipes, Pipe A and Pipe B. The radius of Pipe A is 6 cm, and the radius of Pipe B is 2 cm. What
ss7ja [257]
I beilieve its 3:1. I am not completely sure though

6 0
3 years ago
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