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dimulka [17.4K]
3 years ago
5

(50 points) DOE contains points d(2 3) o(0 0) and e(5 1) which of the following angles are both adjacent and supplementary to DO

E

Mathematics
1 answer:
Alexxx [7]3 years ago
7 0

Answer:

When you join points D(2,3),O(0,0)and E(5,1) which are not collinear it will form a triangle.

Now , Adjacent of ∠ DOE are [ ∠ ODE and ∠OED] .

As we know that  Sum of three interior angles of a triangle is 180°.

∠ DOE + ∠OED+∠EDO = 180°

∠DOE=180°- (∠OED+∠EDO)

Supplementary ,of ∠DOE is  (∠OED+∠EDO).






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Assumed that sides are equal

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Subtract the following complex numbers: (4+4i)-(13+17i) ??
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Jeremy has a weekend job as a soccer referee. One weekend, he earns $140 by working 4 games. Another weekend, he earns $210 by w
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After a weekend at the beach, Lisa has $274 less than she had when she left. The equation that represents this situation is e=s−
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6 0
2 years ago
How do you solve this?
puteri [66]

Answer:

Width: 7

Length: 14

Step-by-step explanation:

The area of a rectangle can be found my multiplying the length by the width. We do not know neither the length nor the width. However, we do know that the length is 7 feet longer than the width. Because we do not know the value of either side, let's let x represent the width.

Since the length is 7 feet longer, we can represent the length by x+7.

Now that we have our values for the length and the width we can multiply them together to find our area.

(x)(x+7)=x^{2} +7x

Now we have our equation, so we can address the changes made by the original question. The original question states that when 7 is added to both the length and width the area becomes 3 times larger. To do so simply increase each side by 7 by adding 7 to the original values.

(x+7)(x+14)

And multiply our area by 3.

3(x^{2} +7x)

set these equal to each other to find your new equation.

(x+7)(x+14)=3(x^{2} +7x)

Now you need to solve for x. To do this first muliply (x+7) and (x+14).

(x+7)(x+14)=\\x^{2} +14x+7x+98=\\x^{2} +21x+98

Then multiply 3(x^{2} +7x)

3(x^{2} +7x)=\\3x^{2} +21x

Now you can begin solving for x.

x^{2} +21x+98=3x^{2} +21x

Subtract x^{2} from both sides.

21x+98=2x^{2} +21x

Subtract 21x from both sides.

98=2x^{2}

Divide by 2.

49=x^{2}

And finally take the sqaure root of both sides.

\sqrt{x^{2} }=\sqrt{49}\\x=7

Remember, because we are dealing with length, there cannot be negative. So while normally we would get both +7 <em>and</em> -7, in this case we <em>only </em>get +7.

Now that we have the value of x, we can plug it into our original values.

For width we simply get 7.

For length we get 7+7=14

To check our answer we cna multiply 7 by 14 to get 98. Then we can add 7 to our length and width to get 14 and 21. Multiply these together and we get 294. 294 divided by 3 is 98, proving our answer correct.

7 0
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