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Mashutka [201]
3 years ago
15

Which of the relations below is not a function?

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0

Answer:

Relations B and E do not represent the function.

Step-by-step explanation:

We know that a function is a relation where each input or x-value of the X set has a unique y-value or output of the Y set.

In other words, we can not have duplicated inputs as there should be only 1 output for each input.

If we closely observe relation B, and E i.e.

  • B) {(3,4), (4,5), (3,6). (6,7)}
  • E) {(3,4), (4,5), (4,6)}

Relation 'B' IS NOT A FUNCTION

Relation B has duplicated or repeated inputs i.e. x = 3 appears twice times. we can not have duplicated inputs as there should be only 1 output for each input.

Thus, relation B is NOT a function.

Relation 'E' IS NOT A FUNCTION

Relation E has duplicated or repeated inputs i.e. x = 4 appears twice times. we can not have duplicated inputs as there should be only 1 output for each input.

Thus, relation B is NOT a function.

Therefore, relations B and E do not represent the function.

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Answer:

2\sqrt{34}

Step-by-step explanation:

Calculate the distance (d) using the distance formula

d = √(x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 2, 4) and (x₂, y₂ ) = (4, - 6)

d = \sqrt{(4+2)^2+(-6-4)^2}

  = \sqrt{6^2+(-10)^2}

  = \sqrt{36+100}

  = \sqrt{136} = \sqrt{4(34)} = \sqrt{4} × \sqrt{34} = 2\sqrt{34}

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3 years ago
Find the domain of
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Answer:

C (x ≥ -6)

Step-by-step explanation:

<u>Algebraic:</u>

The domain of \sqrt{x} is x\geq 0. When transformed 6 units to the left, it becomes x\geq -6

<u>Graphically:</u>

As shown in the attached graph, x\geq -6 .

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4 years ago
HELLLPP ME PLEASSEEE!!!!!
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The similar circles P and Q can be made equal by dilation and translation

  • The horizontal distance between the center of circles P and Q is 11.70 units
  • The scale factor of dilation from circle P to Q is 2.5

<h3>The horizontal distance between their centers?</h3>

From the figure, we have the centers to be:

P = (-5,4)

Q = (6,8)

The distance is then calculated using:

d = √(x2 - x1)^2 + (y2 - y1)^2

So, we have:

d = √(6 + 5)^2 + (8 - 4)^2

Evaluate the sum

d = √137

Evaluate the root

d = 11.70

Hence, the horizontal distance between the center of circles P and Q is 11.70 units

<h3>The scale factor of dilation from circle P to Q</h3>

We have their radius to be:

P = 2

Q = 5

Divide the radius of Q by P to determine the scale factor (k)

k = Q/P

k = 5/2

k = 2.5

Hence, the scale factor of dilation from circle P to Q is 2.5

Read more about dilation at:

brainly.com/question/3457976

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2 years ago
PLEASE HELP ME I MIGHT FAIL <br> What is the area of the shaded region?<br><br> square centimeters
scoray [572]

Answer:

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Step-by-step explanation:

first find the area of the non shaded area

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<span>                   a⁴(3a² - 2a + 1)

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Now, just addum up :      3a⁶ - 2a⁵ + a⁴</span>


7 0
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