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3 years ago

PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!! I NEED TO FINISH THESE QUESTIONS BEFORE MIDNIGHT TONIGHT.

Mathematics

1 answer:

Paul [167]3 years ago

3 0

Answer:

Step-by-step explanation:

Triangle WXY is a right angle triangle.

From the given right angle triangle

WY represents the hypotenuse of the right angle triangle.

With ∠W as the reference angle,

WX represents the adjacent side of the right angle triangle.

XY represents the opposite side of the right angle triangle.

To determine WY, we would apply the Sine trigonometric ratio

Sin θ = opposite side/hypotenuse. Therefore,

Sin 36 = 5/WY

WY = 5/Sin36 = 5/0.5878

WY = 8.5 to the nearest tenth

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Answer:

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Step-by-step explanation:

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2 years ago

Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> 4e2x - 3 - 5 = 0

Deffense [45]

Answer:

Value of x will be 0.1515

Step-by-step explanation:

We have given the equation $4e^{2x}-3-5=0$

We have top fond the value of x using exponent and logarithmic property

So $4e^{2x}-3-5=0$

$4e^{2x}-8=0$

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3 years ago

There are 2,000 eligible voters in a precinct. A total of 500 voters are randomly selected and asked whether they plan to vote f

Ann [662]

Answer:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

$0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753$

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The estimated population proportion for this case is:

$\hat p = \frac{350}{500}=0.7$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

$0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753$

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

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2 years ago

The diameter of a small gear is 16 cm.This is 2.5 cm more than 1/4 of the diameter of a larger gear.What is the diameter of the

bagirrra123 [75]

Diameter of the larger gear х см
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2 years ago

Tanx cosx = 0

shtirl [24]

You're almost finished.

(sin/cos) times cos = 0

Look at the left side. You could write it as (sin x cos) / cos = 0
and simply divide numerator and denominator by the cosine (cancel it).

Then what do you have left ? . . . <u>sin(x) = 0</u> Do I need to finish this for you ?

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3 years ago