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3 years ago

Pls help me answer 10, 11, and 12 thx in advance

Mathematics

1 answer:

NeTakaya3 years ago

7 0

I'll help with 10,

A=b×h÷2 is your equation so I would substitute in the six and eight next.

The base is 6 and the height is 8 so 6×8÷2=A

Then I would do 6×8=48, 48÷2 is 24.

The area is 24 cm squared.

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Which expression is the simplest form of 3(2x + y) + 4(x - 4y) + x2?

g100num [7]

Answer:

x^2 + 10x - 13y.

Step-by-step explanation:

3(2x + y) + 4(x - 4y) + x^2 First apply the Distributive law to the parentheses:

= 6x + 3y + 4x - 16y + x^2 Now add like terms:

= 10x - 13y + x^2.

7 0

3 years ago

Read 2 more answers

What does x equal in 28 = -2-5x

s2008m [1.1K]

X = 6

28 = -2 - 5x
28 + 2 = 5x
30 = 5x
30/5 = 5x/5 (we divide by five on both side because we want x to be by itself)
6 = x

:)

8 0

4 years ago

Consider the function f(x) = x2 + 2x – 35. If one of the zeros of the

Whitepunk [10]

If one zeros is x= -7 then the other zero is x=5

Step-by-step explanation:

We are given the function: $f(x) = x^2 + 2x-35$

If one zeros of the function is x=-7 we need to find other zero of the function.

We can find zeros of the quadratic equation by factorizing the equation

$f(x) = x^2 + 2x-35$

Factorizing the quadratic equation:

$x^2 + 2x-35=0\\x^2-5x+7x-35=0\\x(x-5)+7(x-5)=0\\(x+7)(x-5)=0\\x+7=0\,\,and\,\,x-5=0\\x=-7\,\,and\,\,x=5$

So, if one zeros is x= -7 then the other zero is x=5

Keywords: Solving Quadratic Equation

Learn more about Solving Quadratic Equation at:

#learnwithBrainly

8 0

3 years ago

Can u guys pretty please help

erastova [34]

It should be A and D, no promises

7 0

3 years ago

Gina measured the amount of water her friends drink each day in gallons. The line plot shows the measurements.

vova2212 [387]

Line plots are used to represent data using lines and dots

The difference between the greatest amount of water and the least is 1/2

From the line plot (see attachment), we have the following parameters:

$Least = 8\frac 28$

$Greatest = 8\frac 68$

<h3>Calculating the difference</h3>

The difference (d) is then calculated as:

$d =Greatest -Least$

So, we have:

$d =8\frac 68 -8\frac 28$

Subtract the common terms (8)

$d =\frac 68 -\frac 28$

Take LCM

$d =\frac {6-2}8$

$d =\frac {4}8$

Reduce the fraction

$d =\frac {1}2$

Hence, the difference between the greatest amount of water and the least is 1/2