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den301095 [7]
3 years ago
10

Find tha gcf of 20xy and 24xzy

Mathematics
2 answers:
MrRa [10]3 years ago
7 0

Answer:

the greatest common factor is 4xy

Mkey [24]3 years ago
3 0

Answer:

4xy

Step-by-step explanation:

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Math problem 16. <br><br> Find the value of x, y and z.
enyata [817]

Answer:

sqrt. 244

Step-by-step explanation:

a^2 + b^2 =c^2

10^2 + 12^2 =244

c^2 =244

c= sqrt. 244

7 0
3 years ago
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Jenni is comparing the cost of two packages of socks. One package has 8 pairs of socks for $12. Another package had 3 pairs of s
Oksi-84 [34.3K]
No, because if you add on 6 more dollars to package 2 you would only have 6 socks for 12 dollars and on package A you would have 8 pairs for 12 dollars.
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3 years ago
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What is the degree of the function f(x)=x⁴-5x+8+x²?​
DENIUS [597]

First put it in decreasing power according to x.

x^4-5x+8+x^2

=x^4+x^2-5x+8

Now this question is asking what is the highest degree of x you see in this function.

4 of course.

Therefore the answer to his question is degree of 4.

Done!

7 0
3 years ago
Which formula can be used to describe the sequence?<br><br> -2 2/3,-5 1/3,-10 2/3, -21 1/3, -42 2/3
Kaylis [27]

Correct answer is third option ---C in edge

4 0
3 years ago
Can someone please help me please
Assoli18 [71]
A
Volume of the Cylinder
Givens
H = 60 yards.
Diameter = 20 yards
pi = 3.14

Formula
V = pi * r^2 * h

Calculations
r = d/2
r = 32/2
r = 16

V =  3.14 * 16^2 * 60 
V = 48230 cubic yards [Cylinder's Volume]

Cone
<em>Formula</em> 
V = 1/3 pi r^2 H

<em>Givens</em>
pi = 3.14
r = 16 yards
h = 20 yards

<em>Sub and solve</em>
V = 1/3 3.14 * 16^2 * 20
V = 5359 cubic yards.

<em>Total Volume of the structure</em>
48230 + 5359 = 53589 Cubic Yards

<em>Water Content</em>
The answer to this part requires a proportion.

1 Cubic yard will hold 201.97 gallons.
53589 yd^3 = x

1/201.97 = 53589 /x  [ You should get a pretty big answer]
x = 201.87 * 53589
x = 10 819 092 gallons can be held by the tank. 

10 819 092 gallons <<<< answer

B 
If the height of both the cylinder and the cone remain the same. If the radius doubles in both the cylinder and the cone then the tank will hold 4 times as much. 

Total volume before doubling the radius = pi * r^2 h + 1/3 pi r^2 h
New Total Volume = pi * (2*r)^2 h + 1/3 pi * (2r)^2 h
New Total volume = pi * 4r^2 h + 1/3 pi *4 r^2 h
New Total Volume = 4 [pi r^2 h + 1/3 pi r^2 h]
but pi r^2 h + 1/3 pi r^2 h is the total volume before doubling the radius

New volume = 4 original volume. <<<<< answer to part B
6 0
3 years ago
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