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3 years ago

Suppose that you purchased a water bed with the dimensions 2.55 m Ã 2.53 dm Ã 245 cm. what mass of water does this bed contain

Physics

1 answer:

Nadya [2.5K]3 years ago

6 0

dimensions of the bed is given as

$length = 2.55 m$

$thickness = 2.53 dm = 0.253 m$

$width = 245 cm = 2.45 m$

now the volume of the bed is given as

$V = 2.55 * 0.253 * 2.45 m^3$

$V = 1.581m^3$

now the mass of water in it is given as

$mass = density * volume$

$mass = 1000* 1.581$

$mass = 1581 kg$

<em>so it will contain 1581 kg mass in it</em>

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Answer:

e) True, f) False

Explanation:

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$Q_{net,in} - W_{net, out} = \Delta U$ (1)

Where:

$Q_{net, in}$ - Net input heat, measured in joules.

$W_{net, out}$ - Net output work, measured in joules.

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Please notice that work comprises all kind of work (i.e. mechanical, electric, magnetic), whereas heat comprises all heat interactions including chemical and radioactive phenomena.

If thermal energy is released, then $\Delta U < 0$ , which is caused by three scenarios:

(i) $Q_{net,in} < 0$ , $W_{net, out} < 0$ , $|Q_{net,in}|>|W_{net,out}|$

(ii) $Q_{net, in} > 0$ , $W_{net,out} > 0$ , $|Q_{net,in}|$

(iii) $Q_{net,in}< 0$ , $W_{net, out}>0$

In the case $Q_{net,in} > 0$ , $W_{net, out}$ , the thermal energy of the system is increased. Therefore, thermal energy is released during some energy conversions. Answer: True

f) A liquid solidifies when temperature goes below point of fusion, meaning a realease of heat with no work interactions. That is:

$Q_{net, in} = \Delta U$ , $Q_{net, in} < 0$ (2)

If $Q_{net, in} < 0$ , then $\Delta U < 0$ . Then, if a liquid absorbs heat energy, then thermal energy is increase and the liquid does not solidifies. Answer: False.

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2 years ago

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Answer:

Lead, Ethyl alcohol and water.

Explanation:

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3 years ago

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Answer:

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