Answer:
s = 20 m
Explanation:
given,
mass of the roller blader = 60 Kg
length = 10 m
inclines at = 30°
coefficient of friction = 0.25
using conservation of energy
u = 9.89 m/s
Using second law of motion
ma =μ mg
a = μ g
a = 0.25 x 9.8
a = 2.45 m/s²
Using third equation of motion ,
v² - u² = 2 a s
0² - 9.89² = 2 x 2.45 x s
s = 20 m
the distance moved before stopping is 20 m
Answer:
0.5m/s^2
Explanation:
We can use the formula [ F = ma ] but solve for "a" since that is what we are looking for.
F = ma
F/m = a
We know the net force and mass so substitute those values and simplify.
500/1000 = 0.5m/s^2
Best of Luck!
Momentum = mass x velocity, so 500kg x 2m/s = 1000 kg m/s
Answer:51.44 units
Explanation:
Given
x component of vector is 
y component of vector is 
so position vector is
Magnitude of vector is
|r|=51.44 units
Direction
vector is in 2nd quadrant thus
