Answer:
8.6 m/s
Explanation:
The components of the initial velocity of the ball can be found by using the equations:
where
is the horizontal component
is the vertical component
v is the magnitude of the velocity
is the angle above the horizontal
Substituting:
v = 15 m/s
We find:
There are no acceptable descriptions at all on that list of choices.
Answer:
Explanation:
Given:
- quantity of point charge,
- radial distance from the linear charge,
- linear charge density,
<u>We know that the electric field by the linear charge is given as:</u>
<u>Now the force on the given charge can be given as:</u>
The parcel will undergo projectile motion, which means that it will have motion in both the horizontal and vertical direction.
First, we determine how long the parcel will fall using:
s = ut + 1/2 at²
where s will be the height, u is the initial vertical velocity of the parcel (0), t is the time of fall and a is the acceleration due to gravity.
5.5 = (0)(t) + 1/2 (9.81)(t)²
t = 1.06 seconds
A
The velocity of the ball when it reaches the ground is equal to B. 68.6 m/s. This value was obtained from the formula Vf = Vi + at. Vf is the final velocity. Vi is the initial velocity. The acceleration is "a", while the time of travel is "t". The solution is:
<span>Vf = Vi + at
</span>Vf = 0 + (-9.8 m/s^2) (7 s)
Vf = -68.6 m/s
The negative sign denotes the direction of the ball.
