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timama [110]
3 years ago
7

A 55 newton force applied on an object moves the object 10 meters in the same direction as the force. What is the value of work

done on the object? A. 0 joules B. 5.5 joules C. -5.5 joules D. 5.5 × 102 joules E. -5.5 × 102 joules Reset Next
Physics
1 answer:
kifflom [539]3 years ago
3 0

Answer: Option D: 5.5×10²Joules

Explanation:

Work done is the product of applied force and displacement of the object in the direction of force.

W = F.s = F s cosθ

It is given that the force applied is, F = 55 N

The displacement in the direction of force, s = 10 m

The angle between force and displacement, θ = 0°

Thus, work done on the object:

W = 55 N × 10 m × cos 0° = 550 J = 5.5 × 10² J

Hence, the correct option is D.

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Explanation:

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How to derive the fourth equation of motion?
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An asteroid orbiting the Sun has a mass of 4.00×1016 kg. At a particular instant, it experiences a gravitational force of 3.14×1
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<h2>The asteroid is 4.11 x 10¹¹ m far from Sun</h2>

Explanation:

We have gravitational force

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           Where G =  6.67 x 10⁻¹¹ N m²/kg²

                       M = Mass of body 1

                       M = Mass of body 2

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Here we have

                 M = Mass of Sun = 1.99×10³⁰ kg

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Substituting

                   F=\frac{GMm}{r^2}\\\\3.14\times 10^{13}=\frac{6.67\times 10^{-11}\times 1.99\times 10^{30}\times 4\times 10^{16}}{r^2}\\\\r=4.11\times 10^{11}m

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Explanation:

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