Question

A 55 newton force applied on an object moves the object 10 meters in the same direction as the force. What is the value of work done on the object? A. 0 joules B. 5.5 joules C. -5.5 joules D. 5.5 × 102 joules E. -5.5 × 102 joules Reset Next

Answer 1

Answer: Option D: 5.5×10²Joules

Explanation:

Work done is the product of applied force and displacement of the object in the direction of force.

W = F.s = F s cosθ

It is given that the force applied is, F = 55 N

The displacement in the direction of force, s = 10 m

The angle between force and displacement, θ = 0°

Thus, work done on the object:

W = 55 N × 10 m × cos 0° = 550 J = 5.5 × 10² J

Hence, the correct option is D.