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3 years ago

5

A delivery person uses a service elevator to bring boxes of books up to an office. The delivery person weighs 180 lb and each bo

x of books weighs 40 lb. The maximum capacity of
the elevator is 850 lb. How many boxes of books can the delivery person bring up at one time?

1 answer:

grigory [225]3 years ago

6 0

Answer:

The delivery person can bring up max 16 boxes at one time.

Step-by-step explanation:

The elevator can only hold max 850 lbs, and the delivery man weighs 180 lbs.

850-180=670

That means the delivery man can have up to 670 lbs of boxes on the elevator.

670/40=16.75

Which means that the delivery man can hold up to 16 boxes max at one time.

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A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The plate, including the bound

rjkz [21]

Answer:

We have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . and the hottest value is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

$T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x$

Let's take the partials derivatives.

$T_{x}(x,y)=2x-\frac{3}{2}=0$

$T_{y}(x,y)=4y=0$

So, we can find the critical point (x,y) of T(x,y).

$2x-\frac{3}{2}=0$

$x=\frac{3}{4}$

$4y=0$

$y=0$

The critical point is (3/4,0) so the temperature at this point is: $T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})$

$T(\frac{3}{4},0)=-\frac{9}{16}$

Now, we need to evaluate the boundary condition.

$x^{2}+y^{2}=1$

We can solve this equation for y and evaluate this value in the temperature.

$y=\pm \sqrt{1-x^{2}}$

$T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x$

$T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2$

Now, let's find the critical point again, as we did above.

$T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0$

$x=-\frac{3}{4}$

Evaluating T(x,y) at this point, we have:

$T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2$

$T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$

Now, we can see that at point (3/4,0) we have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . On the other hand, at the point $-(3/4),\frac{\sqrt{7}}{4})$ we have the hottest value of temperature, it is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

I hope it helps you!

4 0

2 years ago

Ms. Kincaid keeps a supply of dimes and quarters in her car to pay for highway tolls. A week’s supply of toll coins contains 5 m

Alecsey [184]

Answer: (A) 10

<u>Step-by-step explanation:</u>

<u>Value</u> <u>Quantity</u> = <u>TOTAL Value</u>

dimes: .10 Q + 5 = .10(Q = 5)

quarters: .25 Q = .25Q

Dimes + Quarters = $4.00

.10(Q + 5) + .25Q = 4.00

.10Q + .50 + .25Q = 4.00

.50 + .35Q = 4.00

.35Q = 3.50

Q = 10

Quarters = 10

Dimes = Q + 5

= 10 + 5

= 15

8 0

3 years ago

Read 2 more answers

Ryan, a baker, measured the weights of cakes baked in each batch at his bakery and found that the mean weight of each cake is 50

denpristay [2]

Answer: Rejecting the mean weight of each cake as 500 gram when H subscript 0 equals 500

Step-by-step explanation:

Given that :

Null hypothesis : H0 =500

Alternative hypothesis : Ha < 500

Type 1 Error: Type 1 error simply occurs when we reject the Null hypothesis when the Null is true. Alternatively, type 11 error occurs when we fail to reject a false null hypothesis.

Hence, in the scenario above, a type 1 error will occur when we reject the mean weight as 500 even though the Null hypothesis is True.

6 0

3 years ago

C and d are complementary. The measure of c is 4x and the measure of d is 26. What is the value of x

const2013 [10]

Answer:

The value of x is 16.

Step-by-step explanation:

We are given the following in the question:

c and d are complementary angles.

Measure of c = $4x$

Measure of d = 26

Since c and d are complementary, we can write from property of complementary:

$c + d = 90$

Putting values, we get,

$4x + 26 =90\\4x = 90-26 = 64\\\\\Rightarrow x = \dfrac{64}{4} = 16$

Thus, value of x is 16.

6 0

3 years ago

Find the vertex and zeros of the following function f(x)=x^2-6x-7

elena-s [515]

Try this solution:

Step-by-step explanation:

1) for zeros of the function: x²-6x-7=0; ⇒ x₁=7; x₂= -1.

2) for the vertex of the function: x₀= -b/2a, where a;b;c - numbers from ax²+bx+c=0 (from x²-6x-7=0).

x₀=6/2=3;

y₀= (4ac-b²)/4a; ⇒ y₀= -16.

It means, the coordinates of the vertex are (3;-16).

6 0

3 years ago