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Leni [432]
3 years ago
5

A delivery person uses a service elevator to bring boxes of books up to an office. The delivery person weighs 180 lb and each bo

x of books weighs 40 lb. The maximum capacity of
the elevator is 850 lb. How many boxes of books can the delivery person bring up at one time?
Mathematics
1 answer:
grigory [225]3 years ago
6 0

Answer:

The delivery person can bring up max 16 boxes at one time.

Step-by-step explanation:

The elevator can only hold max 850 lbs, and the delivery man weighs 180 lbs.

850-180=670

That means the delivery man can have up to 670 lbs of boxes on the elevator.

670/40=16.75

Which means that the delivery man can hold up to 16 boxes max at one time.

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simplify the following expression: (x+7/4x) + (5/x-8) I also attached a photo of the problem if you get confused on how I typed
Gnoma [55]

Answer:

\frac{x^{2}  + 19x - 56}{4 {x}^{2}   - 32x}

Step-by-step explanation:

Start by making the denominators of both fraction the same. This can be done by multiplying one fraction's denominator by the other.

After simplifying and combining the two fractions together, check if the numerator can be factorised such that there is a common factor in the denominator and numerator. In this case, the numerator cannot be factorised.

Lastly, expand the denominator.

\frac{x + 7}{4x}  +  \frac{5}{x - 8}

=  \frac{(x + 7)(x - 8)}{4x(x - 8)}  +  \frac{5(4x)}{4x(x - 8)}

=  \frac{x(x) + x( - 8) + 7(x) + 7( - 8) + 20x}{4x(x - 8)}

=  \frac{ {x}^{2} - 8x + 7x - 56 + 20x }{4x(x - 8)}

=  \frac{ {x}^{2}  + 19x - 56}{4x(x - 8)}

=  \frac{ {x}^{2}  + 19x - 56}{4 {x}^{2}  -  32x}

7 0
2 years ago
I neeeddd help pleaase
Norma-Jean [14]
I got 65 for my answer. Hope that helps!
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3 years ago
Solve the equation<br> x-5=36-7(x+7)
lana66690 [7]

Answer: x = -1

Step-by-step explanation:

1) x - 5 = 36 -7x -49

2) x - 5 = -13 -7x

3) x + 7x =- 13 +5

4) 8x =- 8

5) x = -1

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3 years ago
Y=x^2 -9x at x = 4 Find an equation of the tangent an an equation of the normal
Montano1993 [528]

The tangent line to <em>y</em> = <em>f(x)</em> at a point (<em>a</em>, <em>f(a)</em> ) has slope d<em>y</em>/d<em>x</em> at <em>x</em> = <em>a</em>. So first compute the derivative:

<em>y</em> = <em>x</em>² - 9<em>x</em>   →   d<em>y</em>/d<em>x</em> = 2<em>x</em> - 9

When <em>x</em> = 4, the function takes on a value of

<em>y</em> = 4² - 9•4 = -20

and the derivative is

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Then use the point-slope formula to get the equation of the tangent line:

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<em>y</em> + 20 = -<em>x</em> + 4

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The normal line is perpendicular to the tangent, so its slope is -1/(-1) = 1. It passes through the same point, so its equation is

<em>y</em> - (-20) = 1 (<em>x</em> - 4)

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<em>y</em> = <em>x</em> - 24

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Como resolver logaritmos avanzados​
Firlakuza [10]

Answer:

could u put this in english

5 0
3 years ago
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