(x , y) = (7, - 1)
2x + 3y = 11 → (1)
3x + 3y = 18 → (2)
subtracting (1) from (2) term by term eliminates the y- term
(3x - 2x) + (3y - 3y) = (18 - 11)
x + 0 = 7 ⇒ x = 7
substitute x = 7 into either of the 2 equations and solve for y
(1) → (2 × 7) + 3y = 11
14 + 3y = 11
subtract 14 from both sides
3y = 11 - 14 = - 3
divide both sides by 3
= - 1
solution is (7 , -1)
Answer:
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Step-by-step explanation:
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Arithmetic. The common difference is 6 and the blanks are -15 and -3.
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Answer:
a. I would ask every person in Ms. Tyson's third-period math class how many siblings they have. Then, I would add that those numbers together and divide by the number of people in Ms. Tyson's class to get the average.
b. It would result in a sample statistic because Ms. Tyson's third-period math class is a simply a sample of a population, not the entire population itself. The class is a fraction or percentage of a group as opposed to a whole group.
Answer:
y = -3x - 2
Step-by-step explanation:
Parallel lines have the same slope. The only answer choice with the same slope (x-coefficient = -3) as the given line is the one shown above.
