A flagpole broke in a storm. It was originally 81 8181 feet tall. 28 2828 feet are still sticking straight out of the ground, wh
ere it snapped, but the remaining piece has hinged over and touches the ground some distance away. How far away is the end of the pole from the base of the pole along the ground?
1 answer:
Answer:
The end of the flagpole is 50.79 ft away from the base of the pole.
Step-by-step explanation:
The problem is represented by the diagram below.
The broken flagpole forms the shape of a right angled triangle. We need to find one of the sides of the triangle, the adjacent (x).
The hypotenuse is the broken part of the flagpole (53 ft), while the opposite is the part of the flagpole that is still stuck to the ground (28 ft).
Using Pythagoras theorem, we have that:
=>
The end of the flagpole is 50.79 ft away from the base of the pole.
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now, the bases are parallel, that means the altitude segment is perpendicular to the base, the longest side at the bottom, so, we end up with a right-triangle that has a Hypotenuse and a Leg, equal to the other triangle's.
thus, by the HL theorem for right triangles, both of those triangles are congruent, and if the triangles are congruent, all their sides are also, including the ones on the base.
now, we know that the slanted legs are congruent, since it's an isosceles trapezoid, we also know that the bases are the parallel sides, so, the "altitude" or distance from those bases are the same length, for each of those triangles in the picture.
now, the bases are parallel, that means the altitude segment is perpendicular to the base, the longest side at the bottom, so, we end up with a right-triangle that has a Hypotenuse and a Leg, equal to the other triangle's.
thus, by the HL theorem for right triangles, both of those triangles are congruent, and if the triangles are congruent, all their sides are also, including the ones on the base.
Answer:
Step-by-step explanation:
The given quadratic equation is:
Comparing it with the standard form of Quadratic Equation , we get:
a = 3, b = -9 and c = 1
Discriminant = b² - 4ac
D = (-9)²-4(3)(1)
D = 81 - 12
D = 69