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yaroslaw [1]
3 years ago
12

Please answer all for 50 points and show the answers thank you

Mathematics
1 answer:
melamori03 [73]3 years ago
6 0
What do you need help with? it helps us to know the question!
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Which of the following is correctly written in Standard Form? −3x + 7y = 12, y = 3/7x + 6 ,5x − 4y = 9 ,3/7x + 2y =9
melisa1 [442]
2nd one - y = 3/7x + 6 , hope this helps:)
3 0
3 years ago
Help answer please!!!!
MAVERICK [17]

Answer:

QR ≈ 16.2 ft

Step-by-step explanation:

Using the tangent ratio in the right triangle.

tan62° = \frac{opposite}{adjacent} = \frac{QR}{RP} = \frac{QR}{8.6} ( multiply both sides by 8.6 )

8.6 × tan62° = QR , then

QR ≈ 16.2 ft ( to the nearest tenth )

5 0
3 years ago
Give an example of each of the following, or argue that such a request is impossible.
Masteriza [31]

Answer and Step-by-step explanation:

Solution:

(a) Let (bn) be a bounded sequence of (an) then, Bolzano- Weierstrass theorem,

(bn) contains a subsequence that is converges.

(b) The sequence :

Xn = 1 + (-1) n / 2 + 1/n

Clearly, (xn) does not contain 1 or 0.

If we take sequence (x2n), then it converges to 1 and when we take sequence (x2n+1),

Then it converges to 0.

(c) The sequence:

1

1,1/2

1, 1/2, 1/3

1, 1/2, 1/3, 1/4

i.e

(xn) = (1,1/2, 1, 1/2, 1/3, …)

Then, the subsequence (xn) that is identically ½ in second column and 1/3 is third column and so on.

It has sub sequence that converges to every point in infinite set {1, 1/2, 1/3, 1/4, 1/5…}.

(d) The sequence

{1, 1/2, 1/3, 1/4, 1/5…}

if we take sequence of given set, then, this set converges to zero. This is not contained in it.

If (xn) converges to every point in set {1, 1/2, 1/3 …} then there exists subsequence which converges to 0. And 0 does not belong to given set.

3 0
3 years ago
(06.04)
otez555 [7]

Answer:

5x/3y2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Kase, an individual, purchased some property in Potomac, Maryland, for $217,000 approximately 10 years ago. Kase is approached b
Advocard [28]

The question is incomplete.

The complete question is

Kase, an individual, purchased some property in Potomac, Maryland, for $217,000 approximately 10 years ago. Kase is approached by a real estate agent representing a client who would like to exchange a parcel of land in North Carolina for Kase’s Maryland property. Kase agrees to the exchange.

What is Kase’s realized gain or loss, recognized gain or loss, and basis in the North Carolina property in each of the following alternative scenarios? (Loss amounts should be indicated by a minus sign. Leave no answer blank. Enter zero if applicable.)

a. The transaction qualifies as a like-kind exchange and the fair market value of each property is $907,500.

b. The transaction qualifies as a like-kind exchange and the fair market value of each property is $199,000.

Answer:

A. Realized gain(907500-217000)= 609,500

Recognized gain= 0

Adjustment basis in new property=217,000.

B. Realised loss ( 199000 - 217000) = 18,000

Recognized loss= 0

Adjusted basis in new property= 217000

Step-by-step explanation:

A.

Realized gain(907500-217000)= 609,500

Recognized gain= 0

Adjustment basis in new property=217,000.

Here , we find that Kase has realised gain of $ 690,500 but recognised gain of $ 0 . It is so because Kase did not receive any boot and the transaction is a like-kind exchange. Therefore, the adjusted basis in new property = $ 217,000 ( as no gain is recognised ).

B.

Realised loss ( 199000 - 217000 )= 18,000

Recognized loss= 0

Adjusted basis in new property= 217000

7 0
3 years ago
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