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2 years ago

Name five x values for which the sine function equals to 0. Please help!!

2 answers:

4 0

The five values can be easily found if the value of the first two numbers are known.The value of sine 0 is equal to 0. Now we also come to know that the vale of sin 180 is equal to 0. now if we keep adding 180, we will reach the required answer,. So, the five values are 0, 180, 360, 540 and 720. I hope the answer has helped you.

slega [8]2 years ago

4 0

0, 180, 360, 540, and 720. Hope this helps.

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Assume that the number of watches produced every hour is normally distributed with a mean of 500 and a standard deviation of 100

horsena [70]

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z=(x-</span>μ<span>)/</span>σ
where:
x=500
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σ=100
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2 years ago

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In the given figure ABCD is a tripepizeum with AB||CD. If AO = x-1, CO = BO = x+1 and CD = x+4. Find the value of x.

Hitman42 [59]

$\longmapsto$ The value of "x" is 5.

$\large\underline{\sf{Solution-}}$

Given that,

A trapezium ABCD in which AB || CD such that

AO = x - 1

CO = BO = x + 1

OD = x + 4

Now,

$\rm In \: \triangle \: AOB \: and \: \triangle \: COD$

$\rm \: \angle \: AOB \: and \: \angle \: COD \: \: \{vertically \: opposite \: angles \}$

$\rm \: \angle \:ABO \: and \: \angle \: CDO \: \: \{alternate \: interior \: angles \}$

$\bf \: \triangle \: AOB \: \sim \: \triangle \: COD \: \: \: \{AA \: similarity \}$

$\bf\longmapsto\:\dfrac{AO}{CO} = \dfrac{BO}{DO}$

$\rm \longmapsto\:\dfrac{x - 1}{x + 1} = \dfrac{x + 1}{x + 4}$

$\rm \longmapsto\:(x - 1)(x + 4) = {(x + 1)}^{2}$

$\rm \longmapsto\: {x}^{2} - x + 4x - 4 = {x}^{2} + 1 + 2x$

$\rm \longmapsto\: 3x - 4 = 1 + 2x$

$\rm \longmapsto\: 3x - 2x= 1 +4$

$\bf\longmapsto \:x = 5$

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3 years ago

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