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tekilochka [14]
3 years ago
8

Which equations represent the line that is parallel to 3x – 4y = 7 and passes through the point (-4,-2)? Select two

Mathematics
1 answer:
seropon [69]3 years ago
5 0

Answer:

4y = 3x + 4

3x-4y = -4 is correct

Step-by-step explanation:

This is what we do.

We first express the first equation in the form;

y = mx + c

where m represents the slope of the line

Thus we have;

4y = 3x -7

divide through by 4

y = 3/4x -7/4

Thus the slope here is the coefficient of x which is 3/4

Now, since the lines are parallel, it means that their slopes are equal

So the slope of the other line too is 3/4

We now use the point slope form to find the equation of this other line

Mathematically, that would be;

y-y1 = m(x-x1)

where (x1,y1) = (-4,-2)

Substituting this into the point slope equation, we have;

y-(-2) = 3/4(x-(-4))

y + 2 = 3/4(x + 4)

Cross multiply

4y + 8 = 3x + 12

4y = 3x + 12-8

4y = 3x + 4

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Which of the following triangles are right triangles? select all apply
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Answer:

The following Triangles are Right Triangles:

1.  Δ ABC Where AB = 76 in, BC = 357 in, and AC = 365 in.

2. Δ MIT Where MI = 123 cm, IT = 836 cm, and MT = 845 cm.

3. Δ MEL Where ME = 20 ft, EL = 99 ft, and ML = 101 ft.

Step-by-step explanation:

For a Triangle to be a Right Triangle it must Satisfy Pythagoras theorem.

i.e.

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

For Δ ABC Where AB = 76 in, BC = 357 in, and AC = 365 in.

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∴  AC² = AB² + BC²

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For Δ MIT Where MI = 123 cm, IT = 836 cm, and MT = 845 cm.

MT² = 845² = 71405

MI² + IT² = 123² + 836² = 714025

∴ MT² = MI² + IT²

Hence Δ MIT a Right Triangle.

For  Δ MEL Where ME = 20 ft, EL = 99 ft, and ML = 101 ft.

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∴ ML² = ME² + EL²

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