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2 years ago

The product of a number and negative four is negative twenty-eight. What is the number?

Mathematics

1 answer:

Katyanochek1 [597]2 years ago

6 0

Answer:

The number is 7. If you divide -28 by -4 you get 7, 7×-4=-28

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Find the slope of the line passing through the points (5, 7) and (5, -9)

Fantom [35]

Answer:

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Step-by-step explanation:

To find the slope, we can use the slope formula

m = (y2-y1)/(x2-x1)

= (-9-7)/(5-5)

= (-16)/0

When we divide by zero, the slope is undefined

7 0

2 years ago

A line passes through the points (2, –2) and (–6, 2). The point (a, –4) is also on the line. What is the value of a?

Murljashka [212]

Answer:

Step-by-step explanation:

I took the test

5 0

2 years ago

Read 2 more answers

What is this help please ?

stiks02 [169]

|k - 2| * |3k| - 1
Substitute all of the "k" variables for -4
|-4 - 2| * |3(-4)| - 1
Multiply 3 by -4
|-4 - 2| * |-12| -1
Subtract 2 from -4
|-6| * |-12| - 1
Use the absolute value method
6 * 12 - 1
Combine like terms
Final Answer: 71

5 0

3 years ago

Ms. Pearson kept track of student absences versus final average grades in her math dass for one semester, The

sammy [17]

The correct statement about the data collected by Ms. Pearson is that there is no association between a student's absences and the final average grades.

<h3>When do variables have a linear relationship?</h3>

The equation that represents a linear relationship is: a + bx

Where x represents the rate of increase. Thus, for linear equations, the functiion increases by a constant term.

Looking at the table, the average final grade does not increase by a constant term.

To learn more about linear functions, please check: brainly.com/question/26434260

6 0

1 year ago

A flagpole is located at the edge of a sheer y = 70-ft cliff at the bank of a river of width x = 40 ft. See the figure below. An

Gnom [1K]

I would solve this using tangents. Let h be height of flagpole.
Set up 2 right triangles, each with a base of 40.
The larger triangle has height of "h+70"
Smaller triangle has height of 70.

Now write the tangent ratios:
$tan A = \frac{h+70}{40} , tan B = \frac{70}{40}$

Note: A-B = 9
To solve for h we need to use the "Difference Angle" formula for Tangent
$tan (A-B) = \frac{tanA - tanB}{1+tan A tan B}$
Plug in what we know:
$tan(9) = \frac{ \frac{h+70}{40} - \frac{70}{40}}{1+ (\frac{h+70}{40})(\frac{7}{4})}$
$tan (9) = \frac{ \frac{h}{40}}{ \frac{7h +650}{160}} = \frac{4h}{7h+650}$
$h = \frac{650 tan(9)}{4-7 tan(9)}$
$h = 35.6$

7 0

2 years ago