Answer:
There is no point of the form (-1, y) on the curve where the tangent is horizontal
Step-by-step explanation:
Notice that when x = - 1. then dy/dx becomes:
dy/dx= (y+2) / (2y+1)
therefore, to request that the tangent is horizontal we ask for the y values that make dy/dx equal to ZERO:
0 = ( y + 2) / (2 y + 1)
And we obtain y = -2 as the answer.
But if we try the point (-1, -2) in the original equation, we find that it DOESN'T belong to the curve because it doesn't satisfy the equation as shown below:
(-1)^2 + (-2)^2 - (-1)*(-2) - 5 = 1 + 4 + 2 - 5 = 2 (instead of zero)
Then, we conclude that there is no horizontal tangent to the curve for x = -1.
Answer:
X=32, y=-5
Step-by-step explanation:
Answer:
0.1
Step-by-step explanation:
If -3 + i is a root of the polynomial function f(x), -3 - i must also be a root of f(x)
<h3>How to determine the true statement?</h3>
The root of the polynomial function is given as:
-3 + i
The above root is a complex root.
If a polynomial has a complex root, then the conjugate of the root is also a root of the function
The conjugate of -3 + i is -3 - i
Hence, if -3 + i is a root of the polynomial function f(x), -3 - i must also be a root of f(x)
Read more about polynomial functions at:
brainly.com/question/20896994
Answer:
-3/4
Step-by-step explanation:
-5/4 + 2/4 = -3/4
Hope this helps :)
