Answer:
8 cm
Step-by-step explanation:
Megan's scale of drawing : car is 3cm : 2m
or
3 cm drawing ---> 2m actual length
1 cm drawing ---> (2/3) m actual length
Given Megan's drawing is 6 cm, hence,
6 cm drawing ----> (2/3) x 6 m = 4 m
Hence the actual car is 4 m long
Ivan's scale of drawing:car is 2cm : 1m
or
1 m actual length ---> 2 cm drawing
we know from above that the actual car is 4m long, so
4m actual length ---> 2cm x 4 = 8 cm drawing length.
There are 4 foutains along the runnong trail
Answer: x=67/2
HOPE THIS HELPS PLLZ GIVE BRAINLEST :)
A ) x² - 10 x - 14 = 0 and ( 2 x - 10 )² = 156 T ( True )
( 2 x - 10 )² - 156 = 04 x² - 40 x + 100 - 156 = 04 x² - 40 x - 56 = 0 / : 4x² - 10 x - 14 = 0
B ) ( x - 10 )² = 68 and x² - 20 x = - 32 / T ( True )
( x - 10 )² = 68 x² - 20 x + 100 = 68x² - 20 x = 68 - 100x² - 20 x = - 32
C ) x² - 6 x = 247 and ( x - 3 )² = 256 / T ( True )
( x - 3 )² = 256x² - 6 x + 9 = 256x² - 6 x = 247
D ) ( x + 5 )² = 65 and x² = 90 - 10 x / F ( False )
( x + 5 )² = 65x² + 10 x + 25 = 65x² = 65 - 25 - 10 xx² = 40 - 10 x
Hope this helped! (: