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Molodets [167]
2 years ago
11

Help please I will give a brainliest

Mathematics
1 answer:
andreyandreev [35.5K]2 years ago
8 0
The other person is correct the answer is C
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Help me pleaseeeeeeee
Ber [7]

Answer:

72°

Step-by-step explanation:

just add the two smaller angles to get the whole angle

45.3 + 26.7 = 72.0

7 0
2 years ago
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In the diagram below, points A and B represent two airplanes. How far apart are the airplanes?
AleksAgata [21]

Using the Law of Cosines:

d= √(840^2 + 800^2 - 2*840*800*cos(105))

d = √1693452.796

d = 1301 miles.

The answer is B.

7 0
3 years ago
The marked price of a dozen of copies is Rs 600. If the shopkeeper allows 20% discount and then charges 10% VAT, how many copies
aalyn [17]

Answer:

sassy

Step-by-step explanation:

3 0
2 years ago
A sock drawer contains eight navy blue socks and five black socks with no other socks. If you reach in the drawer and take two s
Rzqust [24]

Answer:

a. the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b. the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c. the probability of either 2 navy socks is picked or one black  & one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

Step-by-step explanation:

A sock drawer contains 8 navy blue socks and 5 black socks with no other socks.

If you reach in the drawer and take two socks without looking and without replacement, what is the probability that:  

Solution:

total socks = N = 8 + 5 + 0 = 13

a) you will pick a navy sock and a black sock?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick the black sock, total number of socks left is 12.

Let B be the probability of picking a black sock again.

 P (B) = 5/12.

Then, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

b) the colors of the two socks will match?

Let A be the probability of picking a navy socks first.

Then P (A) = 8/13

without replacing the navy sock, will pick another navy sock, total number of socks left is 12.

Let B be the probability of another navy sock again.

 P (B) = 7/12.

Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

Let D be the probability of picking a black socks first.

Then P (D) = 5/13

without replacing the black sock, will pick another black sock, total number of socks left is 12.

Let E be the probability of another black sock again.

 P (E) = 4/12.

Then, the probability of picking 2 black sock = P (D & E)

= (5/13 ) * (4/12) = 5/39 = 0.128

Now, the probability of picking two navy or two black is

= 56/156 + 20/156 = 76/156 = 0.487

c) at least one navy sock will be selected?

this means, is either you pick one navy sock and one black or two navy socks.

so, if you will pick a navy sock and a black sock, the probability of picking a navy sock and a black sock = P (A & B)

= (8/13 ) * (5/12) = 40/156 = 0.256

also, if you will pick 2 navy sock, Then, the probability of picking 2 navy sock = P (A & B)

= (8/13 ) * (7/12) = 56/156 = 0.359

now either 2 navy socks is picked or one black  one navy socks.

= 40/156 + 56/156 = 96/156 = 0.615

4 0
2 years ago
How do I solve this problem <br> 15 = w + 4
vova2212 [387]

Answer:

w = 11

Step-by-step explanation:

<u>Step 1:  Subtract 4 from both sides</u>

15 = w + 4

15 - 4 = w + 4 - 4

11 = w

Answer: w = 11

3 0
3 years ago
Read 2 more answers
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