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3 years ago

How to change 3/4 to twelfths

Mathematics

2 answers:

ruslelena [56]3 years ago

6 0

Multiply both sides of the fraction by 3.

3/4 = 9/12

Gwar [14]3 years ago

5 0

You take 3/4 and multiply it by 3 because 3 times four is 12 and u get 9/12

Please mark as brainliest asnwer

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Simplify (-3k + p – 1) – (2k – 6p – 2)

Rom4ik [11]

Answer:

-5k+7p+1 I THINK

Step-by-step explanation

destribute the negative

(-3k + p – 1) – (2k – 6p – 2)

-2k+6p+2

add to the (-3k + p – 1) to simplify

-5k+7p+1

3 0

3 years ago

How the graph of y=2x is the same and different from the graph of y=2x-7

solong [7]

The graphs have the same slope (2) and are parallel

The difference is the y intercept

y = 2x has as y intercept of 0

where y = 2x-7 has a y intercept of -7

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4 years ago

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Who was the President in 1991?

ser-zykov [4K]

George H.W Bush.......................

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3 years ago

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I've been stuck on this question for a while now, I need help!

MaRussiya [10]

In order to solve it you must make each component negative. Multiply them by negative one!

M < 2

Now which numbers would satisfy it? M is less than two... so, m could be one, or any negative number, yeah?

Multiply by negative one. - M and -2 are what you have. If it were one... negative one is less than negative two. Turns out M is less than two.

M < 6

M is less than six. It could be 1, 2, 3, 4, or 5.

-M and -6

Is negative 3 less than -6? All of the numbers are! So, m is actually less than 6

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3 years ago

A researcher is interested in finding a 95% confidence interval for the mean number minutes students are concentrating on their

Sever21 [200]

Answer:

A. Normal

B. Between 40.08 minutes and 43.92 minutes.

C. About 95 percent of these confidence intervals will contain the true population mean number of minutes of concentration and about 5 percent will not contain the true population mean number of minutes of concentration.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

x% confidence interval:

A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.

Question A:

By the Central Limit Theorem, a normal distribution.

Question B:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.96\frac{12}{\sqrt{150}} = 1.92$

The lower end of the interval is the sample mean subtracted by M. So it is 42 - 1.92 = 40.08 minutes

The upper end of the interval is the sample mean added to M. So it is 42 + 1.92 = 43.92 minutes

Between 40.08 minutes and 43.92 minutes.

Question C:

x% confidence interval -> x% will contain the true population mean, (100-x)% wont.

So, 95% confidence interval:

About 95 percent of these confidence intervals will contain the true population mean number of minutes of concentration and about 5 percent will not contain the true population mean number of minutes of concentration.

3 0

3 years ago