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horrorfan [7]
3 years ago
14

How many different ways can the letters of ​" accommodate​" be​ arranged?

Mathematics
2 answers:
Mariulka [41]3 years ago
8 0
Here is your answer.....

pychu [463]3 years ago
8 0

Answer:

2,494,800

Step-by-step explanation:

"Accommodate" has n = 11 letters.

Without repeated letters the answer would be 11! = 39,916,800.

But there are 4 letters repeated twice, these are: (a, c, o, m).

Then the solution is to divide 11! by 2! multiplied 4 times to compensate for duplications, that is:

          11!              39,916,800        39,916,800

X = -------------- =  -------------------- = ------------------- = 2,494,800

      2! 2! 2! 2!       2 . 2 . 2 . 2               16

Then, the letters of ​"accommodate​" can be​ arranged of 2,494,800 different ways

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=======================================================

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The equation 9x-4y=-20 has A = 9, B = -4 and C = -20.

That means Ax+By = D becomes 9x-4y = D.

------------------------------

Plug in the coordinates (x,y) = (4,7) and compute the value of D.

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----------------------------

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