Question

Charlie paid 660 for 6 shirts and four belts. One shirt costs three times as much as one belt. If Sam bought 5 shirts and 2 suck belts, how much would he have to pay

Answer 1

Sam would have to pay $510 to buy 5 shirts and 2 suck belts.

Step-by-step explanation:

Let,

Cost of one shirt = x

Cost of one belt = y

According to given statement;

6x+4y = 660    Eqn 1

x = 3y          Eqn 2

Putting value of x from Eqn 2 in Eqn 1

$6(3y)+4y=660\\18y+4y=660\\22y=660$

Dividing both sides by 22

$\frac{22y}{22}=\frac{660}{22}\\y=30$

Putting y=30 in Eqn 2

$x=3(30)\\x=90$

One shirt costs $90 and one belt cost $30.

Price of 5 shirts = 90*5 = $450

Price of 2 belts = 30*2 = $60

Total = 450+60 = $510

Sam would have to pay $510 to buy 5 shirts and 2 suck belts.

Keywords: linear equation, addition

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