Answer:
Step-by-step explanation:
Given that a parking lot has two entrances. Cars arrive at entrance I according to a Poisson distribution at an average of 3 per hour and at entrance II according to a Poisson distribution at an average of 2 per hour.
Assuming the number of cars arriving at the two parking lots are independent we have total number of cars arriving X is Poisson with parameter 3+2 = 5
X is Poisson with mean = 5
the probability that a total of 3 cars will arrive at the parking lot in a given hour
= P(X=3) = 0.1404
b) the probability that less than 3 cars will arrive at the parking lot in a given hour
= P(X<3)
= P(0)+P(1)+P(2)
= 0.1247
Answer:
a = -1.58
Step-by-step explanation:
1/3 +a+5/4 =0
1/3+5/4= -a
4+15/12 = -a
19/12 = -a
1.58= -a
1.58/-1 = -a/-1
-1.58 = a
Answer:
To get to -3 you can do 1+-4
Answer:
6
Step-by-step explanation:
2 goes into 6 evenly so two times three equals six so you multiply 1 by three and it gives you 3/6
