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kompoz [17]
3 years ago
8

4friends shared a pitcher of juice 6/24 2/16 5/16 4/32 which 2 would have drank 1/4 of the juice

Mathematics
1 answer:
Annette [7]3 years ago
3 0
6/24 and 5/16 are the two friends who would have drank 1/4 of the juice.
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At the theater, the Garcia family bought 2 adult tickets and 3 children's tickets for $44.50. The Smith family bought 3 adult ti
kondaur [170]

Answer:

Adult= $11

Children = $7.5

Step-by-step explanation:

Let x represent adult ticket and y represent children ticket

2x + 3y= 44.50........equation 1

3x + 6y= 78........equation 2

From equation 1

2x + 3y= 44.50

2x= 44.50-3y

x= 44.50-3y/2

Substitute 44.50-3y/2 for x in equation 2

3x+ 6y= 78

3(44.50-3y/2) + 6y= 78

66.75- 4.5y +6y= 78

66.75 + 1.5y= 78

1.5y= 78-66.75

1.5y= 11.25

y= 11.25/1.5

y = 7.5

Substitute 7.5 for y in equation 1

2x + 3y = 44.50

2x + 3(7.5)= 44.50

2x + 22.5= 44.50

2x = 44.50-22.5

2x= 22

x= 22/2

x= 11

Hence the price of adult ticket is $11 and the price of children ticket is $7.5

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3 years ago
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Step-by-step explanation:

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In an analysis of healthcare data, ages have been rounded to the nearest multiple of 5 years. The difference between the true ag
Mashcka [7]

Answer:

The correct answer is D. 0.77

Step-by-step explanation:

X_i \text{ is the difference between true and reported age. where i = 1,2,3......48 }\\\text{The rounded age are uniformly distributed. So, }X_i = 0\\\\and,\thinspace O_{X_i}^2=\frac{\text{(Upper Bound - Lower Bound})^2}{5\times 2.5\text{ ( Rounded value )}}\\\\O_{X_i}^2=\frac{(2.5 + 2.5)^2}{12}\approx 2.083\\\\O_X_i=1.443

\bar{X_{48}}=\frac{X_1+X_2+.......+X_{48}}{48}\\\\\bar{X_{48}}=\frac{\frac{48}{X_i}}{48}=0\\\\O_{\bar{X}_{48}}^2=\frac{48\cdot O_{X_i}^2}{48^2}=\frac{O_{X_i}^2}{48}\\\\\text{So, }\bar{X_i}\text{is approximately normal with mean 0 and standard deviation = }\\\\\frac{1.443}{\sqrt{48}}\approx 0.2083

=Pr[\frac{-1}{4}\leq \bar{X}_{48}\leq \frac{1}{4}]\\\\=Pr[\frac{-0.25}{0.2083}\leq Z\leq \frac{0.25}{0.2083}]\\\\=Pr[-1.2\leq Z\leq 1.2]\\=Pr(Z\leq 1.2)-Pr(Z\leq -1.2)\\=Pr(Z\leq 1.2)-(1-Pr(Z\leq 1.2))\\=2\times 0.8849 -1\text{ ( Z value for 1.2 is 0.8849 )}\\\approx 0.77

Hence, the correct answer is 0.77


7 0
3 years ago
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