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2 years ago

14

Bo and Erica are yoga instructors. Between the two of them, they teach 33 yoga classes each week. If Erica teaches 15 fewer than

twice as many as Bo, how many classes does each instructor teach per week?

2 answers:

pav-90 [236]2 years ago

7 0

Bo: 30 classes ?

Erica: 3 classes ?

I think this is the answer.

abruzzese [7]2 years ago

6 0

9 i think is the answer

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Edmond went to the doctor for a check up. When he got home he told his mother that he weighs 1,360 ounces and is 62 inches tall.

Viktor [21]

Please provide the reference sheet.

8 0

3 years ago

Determine the center and radius of the following circle equation:

UkoKoshka [18]

Answer:

The equation of the circle <em>(x + 5 )² + ( y + 10 )² = (4)²</em>

<em>Center of the circle ( h, k) = ( -5 , -10)</em>

<em>Radius of the circle ' r' = 4</em>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given circle equation is x² + y² +10 x + 20 y +109 =0

x² +10 x + y² + 20 y +109 =0

x² +2 (5) (x)+(5)² -(5)²+ y² +2(10) y + (10)²-(10)² +109 =0

<em>By using formula </em>

<em>(a+b)² = a² + 2 a b + b²</em>

<em>(x + 5 )² + ( y + 10 )² - 25 - 100 + 109 = 0</em>

<em>(x + 5 )² + ( y + 10 )² - 16 = 0</em>

<em>(x + 5 )² + ( y + 10 )² = 16</em>

(x + 5 )² + ( y + 10 )² = (4)²

The standard equation of the circle ( x - h )² + ( y -k)² = r²

<em> Center of the circle ( h, k) = ( -5 , -10)</em>

<em>Radius of the circle ' r' = 4</em>

<u><em>Conclusion</em></u><em>:-</em>

The equation of the circle <em>(x + 5 )² + ( y + 10 )² = (4)²</em>

<em>Center of the circle ( h, k) = ( -5 , -10)</em>

<em>Radius of the circle ' r' = 4</em>

<em></em>

3 0

3 years ago

Effie ate 4 peaches. this represents 25% of the bag of peaches. how many peaches were originally in the bag

pav-90 [236]

16 peaches were originally in the bag.
16/25%=4

5 0

2 years ago

Given a right triangle with a hypotenuse of 6 cm and a leg of 4cm, what is the measure of the other leg of the triangle rounded

slega [8]

Answer:

$4.5 cm=L2$

Step-by-step explanation:

This problem can be solved using the pythagorian theoreme:

$H=\sqrt{L1^{2}+L2^{2} }$

Where:

$H=6 cm$

$L1=4 cm$

$L2=?$

We isolate our incognita an we get:

$\sqrt{H^{2}-L1^{2}} =L2$

We supplant with the given data:

$\sqrt{(6cm)^{2}-(4cm)^{2}} =L2$

$\sqrt{36cm^{2}-16cm^{2}} =L2$

$\sqrt{36cm^{2}-16cm^{2}} =L2$

$\sqrt{20cm^{2}} =L2$

$4.5 cm=L2$

5 0

3 years ago

Can you help me on this

grigory [225]

Answer:

The answers are x < -65, x > 85, x < 180, x<= -13, and x >=25.

Step-by-step explanation:

For the first three, there's an open circle so the sign for the inequality would be < or > but for the last two, there's a closed circle so the sign for the inequality would be <= or >=, the ones with a line underneath. For 1, 3, and 4, the line goes to the left, showing that x is a number less than the point so it would have <, the less than sign. For 2 and 5, the line goes to the right, showing that x is a number greater than the point so it would have >, the greater than sign.

There's a trick to figuring out the right sign. If the line is pointing to the left, the inequality would be x < __, and the sign is pointng to the left. If the line is pointing to the right, the inequality would be x > __, and the sign is pointng to the right. This only works is x is on the left side of the inequality.

7 0

2 years ago