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STatiana [176]
3 years ago
13

What the answer to this asap

Mathematics
2 answers:
Harman [31]3 years ago
8 0

Answer:

? = 24

Step-by-step explanation:

Since the figures are similar then the ratios of corresponding sides are equal, that is

\frac{?}{18} = \frac{20}{15} ( cross- multiply )

15? = 360 ( divide both sides by 15 )

? = 24

Kitty [74]3 years ago
5 0

Answer:

? is 24

Step-by-step explanation:

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Answer:

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18th: 53

Step-by-step explanation:

The pattern is adding 3 each time:

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Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

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3 years ago
Find each quotient using long division. Just type the number answer in the blank.<br> Pleaseeee help
sergey [27]

Answer: 321 for #1 and 52 for #2

Step-by-step explanation: I divided and got 321 for #1 and 52 for #2.

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