If x is the first of the integers then the statement is:
(x) , (x+2) , (x+4) , (x+6)
This means that the smallest is x and the largest is x + 6
so:
3(x) + 2(x+6) = 293
3x + 2x + 12 = 293
5x = 281
x = 56.2
This gives us a none integer (decimal)
What now?
Wait remember how x started as the lowest? what if x was the highest instead?
x, x-2, x-4, x-6
so:
3(x-6) + 2(x) = 293
5x = 315
x = 62.2
This is as close as have gotten to the answer
Cant seem to get an integer.
Maybe error in the question or some bad math on my part.
Answer:
k=2
Step-by-step explanation:
3^k*2 * 3^-k+2 = 81
Factor out 81 to be : 3^4
Rewrite the equation:
k*2 - k+2 = 4
k^2 - 2k = 4
Simplify : k+2 = 4
<u> - 2 - 2</u>
k = 2
Answer:
60
Step-by-step explanation:
5+5+5+5+5+5+5+5+5+5+5+5
$11.40 because you just divide 35.34 by 3.1
4 up and 6 right
i hope this helped
