Answer:
TRUE
Step-by-step explanation:
We are given 2 triangles, ∆ABC and ∆DEF.
For the two trinagles to be considered similar, both must have their set of corresponding angles congruent to each other. That is, their corresponding angles are equal.
From the information given, the following are the set of corresponding angles:
<B = <E = 31°
<B = <D = 90°
<C = <F = 59° [180 - (90+31)]
The corresponding angles of both triangles are congruent. Therefore, it is guaranteed that ∆ABC is similar to ∆DEF (∆ABC ~ DEF).
Step 1: Flip the equation.
44b+11c=a
Step 2: Add -44b to both sides.
44b+11c+−44b=a+−44b
11c=a−44b
Step 3: Divide both sides by 11.
11c11=a−44b11
c=111a−4b
Answer:
c=111a−4b
Answer:
the answer is D {-5, -13}
Answer:
D
Step-by-step explanation:
because we know that angle EOD is less the 90 so that means that it is complementary. For AOB it is the same but we can check by adding 35 plus x plus 90 =180 degrees so 35+90=125 x=180-125=55 so x=55 and 55 is less then 90 so it is a complementary angle.
Answer:
20
Step-by-step explanation:
4 + 2 + 5 + 4 + 0 + 1 + 1 + 3 = 20
