A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).
<h3>Calculate the vertices of ΔA'B'C':</h3>
Given that,
ΔABC : A(-6,-7), B(-3,-10), C(-5,2)
(x,y)→(x,y-3)
The vertices are:
- A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
- B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
- C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)
Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).
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Answer:
Thickens (Height) = 0.068 cm
Step-by-step explanation:
Given:
Diameter of disc = 14 cm
Radius of disc = 14 / 2 = 7 cm
Surface area = 3 cm²
Find:
Thickens (Height)
Computation:
Disc is a cylinder in shape
Surface area = 2πrh
3 = 2(22/7)(h)(7)
3 = 44(h)
Thickens (Height) = 0.068 cm
Area = square of the measure of a side = 3^(2/7) * 3^(2/7)
= 3 ^(2/7 + 2/7) = 3^(4/7)
Option 2