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Ilya [14]
3 years ago
15

Six pipes are laid end to form a row.each pipe is 9 1/3 inches long.how long is the row of pipes in feet?

Mathematics
1 answer:
laiz [17]3 years ago
3 0

six pipes are laid end to end to form a row. Each pipe is 9 1/3 inches long. how long is the row of pipes, in feet?

Answer:

4.67 feet or 4 feet 8 inches or 4\frac{2}{3}feet

Step-by-step explanation:

Let x be the length of the row pipes.

Given:

Number of pipes = 6

Each pipe has length 9\frac{1}{3} inches. and six pipes are laid end to end to form a row.

The total length of the row is equal to length of the 6 pipes.

So, total length of row = Number of pipes \times Length of the pipe

x=\frac{28}{3}\times 6

x=28\times 2

x=56 inches

convert inch into feet.

x=\frac{56}{12}

x=4.67 feet

Therefore, The length of the row is 4.67 feet or 4 feet 8 inches or 4\frac{2}{3}feet .

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Step-by-step explanation:

a. First person;

y = x² + 11x + 18

y = x² + 9x + 2x + 18

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b. Second person;

y = -5x + 20

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c. Third person;

y = x² - 2x - 15

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d. Fourth person;

y = x² - 49

Applying the difference of squares formula;

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A cylinder has radius r and height h. A. How many times greater is the surface area of a cylinder when both dimensions are multi
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Answer: A. Factor 2 => 4x greater

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A = 2.π.r.h

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A_{1} = 2πrh

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A_{2} = 2.π.2r.2h

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Comparing A_{1} to A_{2} :

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Doubling radius and height creates a surface area of a cylinder 4 times greater.

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Comparing areas:

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The new area is 25 times greater.

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