1 is 9,000 just round up or down and then mulitpy
2 is 6,400
3 is 11,100
4 is 1,200
5 is 189,000
6 is 6,300
7 is 53,000
8 is 4,300
9 is 7,800
that all i can do they might not all be right
Answer:
The answer to your question is:
Step-by-step explanation:
1.-
Data
3.3 x 10 ⁴ pounds of paper
1.5 x 10³ pounds of aluminum
Amount of aluminum / amount of paper = 1.5 x 10³ / 3.3 x 10⁴
= 0.045 times
= 4.5 x 10 ⁻²
2.-
Data
1.2 x 10 ³ text messages in a month
text messages in a year = ?
1.2 x 10³ text messages ------------------- 1 month
x ------------------- 12 months
x = (12 x 1.2 x 10³) / 1
x = 14400 text messages
x = 1.44 x 10⁴ text messages
3.-
Data
distance = 4 x 10⁶ miles I am not sure if the power is 6 or 8
speed = 1.6 x 10³ mi/h
Formula
time = distance / speed
time = 4 x 10⁶ / 1.6 x 10³
time = 2500 h
time = 2.5 x 10 ³ h
Answer:
541 (484) 783, 437 (410) 642
Step-by-step explanation:
Required
Fill in the bracket
First, we generate a formula for the first sequence: 541 (484) 783
![484 = 2 * [783 - 541]](https://tex.z-dn.net/?f=484%20%3D%202%20%2A%20%5B783%20-%20541%5D)
![484 = 2 * [242]](https://tex.z-dn.net/?f=484%20%3D%202%20%2A%20%5B242%5D)


Using the same formula for the second sequence: 437 (?) 642
![x = 2 * [642 - 437]](https://tex.z-dn.net/?f=x%20%3D%202%20%2A%20%5B642%20-%20437%5D)
Where x represents the empty bracket
![x = 2 * [205]](https://tex.z-dn.net/?f=x%20%3D%202%20%2A%20%5B205%5D)

