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Hoochie [10]
3 years ago
13

Please I need help!!!

Mathematics
1 answer:
S_A_V [24]3 years ago
6 0
Hello : 
f(x) = (x − h)2 + k: a <span> vertex of( 2, 3)
h=2 and k=3</span>
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HELP WILL REWARD BRAINLIEST Which is the solution to the equation 3.5 (2h + 4.5) = 57.75? round to the nearest tenth if necessar
krok68 [10]
3.5(2h+4.5)=57.75
7h+15.75=57.75
7h=57.75-15.75
7h=42
h=42/7
h=6
7 0
3 years ago
Read 2 more answers
If sin(2x) = cos(x + 30°), what is the value of x?
valkas [14]

Answer:

x = -10 ° + π/6 + (2 π n_1)/3 for n_1 element Z

or x = 30 ° + π/2 + 2 π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

sin(2 x) = cos(x + 30 °)

Rewrite the right hand side using cos(θ) = sin(θ + π/2):

sin(2 x) = sin(30 ° + π/2 + x)

Take the inverse sine of both sides:

2 x = -30 ° + π/2 - x + 2 π n_1 for n_1 element Z

or 2 x = 30 ° + π/2 + x + 2 π n_2 for n_2 element Z

Add x to both sides:

3 x = -30 ° + π/2 + 2 π n_1 for n_1 element Z

or 2 x = 30 ° + π/2 + x + 2 π n_2 for n_2 element Z

Divide both sides by 3:

x = -10 ° + π/6 + (2 π n_1)/3 for n_1 element Z

or 2 x = 30 ° + π/2 + x + 2 π n_2 for n_2 element Z

Subtract x from both sides:

Answer:  x = -10 ° + π/6 + (2 π n_1)/3 for n_1 element Z

or x = 30 ° + π/2 + 2 π n_2 for n_2 element Z

6 0
3 years ago
2(3-1)^2 / 1+1 x 3+3
zzz [600]
2(3-1) ² / 1+1 x 3+3
Use PEMDAS
2(2) ²/1+1 x 3+3
4 ² / 2x6
16/12
1.333
6 0
3 years ago
Is the midpoint of a line segment is found by averaging the x coordinates and averaging the y coordinates of the endpoints
Serhud [2]
Yes, that's the definition of "midpoint."

                      xa + xb
xmidpoint = --------------
                           2

                      ya + yb
ymidpoint = --------------
                           2
6 0
3 years ago
PLZ HELP ASAP RIGHT TRIANGLES
borishaifa [10]
The correct answer is: AB = 3.11

Explanation:
Since

cos(\theta) =  \frac{base}{hypotenuse} --- (1)
\theta = 50°
base = 2

And hypotenuse = AB

Plug in the values in (1):
(1) => cos(50°) = 2/AB

=> AB = 2/0.643
=> AB = 3.11
6 0
4 years ago
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