Answer:
E. 0.759
Step-by-step explanation:
You can take this right triangle to have a base length side LM , height of LN and a hypotenuse of MN
The sine of angle ∠LMN is 0.759, find the value of ∠LMN

∠LMN=49.38°
Find angle ∠LNM
You know sum of angles in a triangle add up to 180°, given that this is a right-triangle, the base angle is 90° hence
∠LNM=180°-(90°+49.38°)
∠LNM= 180°-139.38°=40.62°
Find cos 40.62°
Cos 40.62°=0.7590
Answer:
600÷60=10
Step-by-step explanation:
six hundred is ten times sixty
Answer:

Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
we know that
The figure shows a kite
The kite has two pairs of consecutive and congruent sides and the diagonals are perpendicular
That means
TS=VS
TQ=VQ
TR=RV
we have


so

solve for x

<em>Find the value of RV</em>

substitute the value of x

Remember that
---> by segment addition postulate
we have

so

Answer:
Krishna's marks x marks
so...
xˉ=15
xˉ=15n=10
xˉ=15n=10∑x=x+x−8+x−6+x−3+x−1+x+x+2+x+3+x+4+x+6=10x−3
15=10x-3/10
150+3=10x
x=150/10=15.3 marks
<em><u>Krishna scored 15.3 marks.</u></em>
<em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>sis</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>