Dennis = 12 km'h
Kathy = 20 km/h
Step-by-step explanation:
- Lets first establish that time is the same for both Kathy and Dennis and we can therefore assign is the value of <em>t</em>
- Kathy is cycling 8km/h faster than Dennis. Therefore if Dennis is doing <em>x </em>km/h Kathy is doing (<em>x</em>+8)km/h
- If it takes Kathy<em> t </em>time to cycle for 60 km at (<em>x</em>+8)km/h, we can derive the time <em>t </em>as;
(<em>x</em>+8)* <em>t </em>= 60
<em>t</em> = 60/(<em>x</em>+8)
- We can now use this time to establsish how fast Dennis is cycling. Dennis, using a speed of <em>x</em> km/h takes the same time (60/(<em>x</em>+8)) to cycle for 36 km. Therefore;
<em>x</em> * 60/(x+8) = 36
= 60x/(x+8) = 36
36 (x + 8) = 60x
36x + 288 = 60x
288 = 60x – 36x
288 = 24x
12 =<em> x </em>
Dennis is cycling at 12 km/h
Kathy is doing x + 8
= 12 + 8 = 20 km/h
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Answer:
x=4
Step-by-step explanation:
Hey there!
I am going to use this image as an example so you can understand the formula
The formula for problems like these is
B(BA)=D(DC)
So all we have to do is plug in the numeric values
so now we have 5(5+x+3)=6(6+x)
now we just solve for x
5(5+x+3)=6(6+x)
step 1 distribute the 5 to what is in the parenthesis (5, x and 3)
5x5=25
5*x=5x
5x3=15
so now we have
25+5x+15=6(6+x)
step 2 distribute the 6 to what is in the parenthesis (6 and x)
6x6=36
6*x=6x
now we have
25+5x+15=6x=36
step 3 combine like terms, the only like terms are 25 and 15
15+25=40
now we have
40+5x=6x+36
step 4 subtract 5x from each side
5x-5x cancels out
6x-5x=x
now we have
40=x+36
step 5 subtract 36 from each side
40-36=4
36-36 cancels out
now we have
x=4 so we can conclude that x=4
hope this helps :)
5 times 1/10 is 5/10 or 1/2 of a kg. This equals 0.5 kg. You can do 3 experiments (use up until 4.5 kg)
Answer:x = 1.5
Step-by-step explanation:
3 = x / 2
First get rid of / 2
3/2 = 1.5
:D
Answer:
thats 300 grams filtered out per hour
Step-by-step explanation:
so 4/4ths of 400 is 400 but taking 3/4ths is turning it too 100 grams
