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3 years ago

<1 and <2 are complementary. Solve for the measure of <1.

Mathematics

1 answer:

Anon25 [30]3 years ago

3 0

Answer:

A) 52

Step-by-step explanation:

If < 1 and < 2 are complementary angles, then it means that the sum of their measures add up to 90°.

< 1 + < 2 = 90°

12x + 4 + 9x + 2 = 90°

21x + 6 = 90°

21x + 6 - 6 = 90° - 6

21x = 84°

21x/21 = 84°/21

x = 4

Substitute the value of x = 4 into < 1 and < 2:

m < 1: 12x + 4 = 12(4) + 4 = 52°

m < 2: 9x + 2 = 9(4) + 2 = 38°

Therefore, the correct answer is A) m < 1 = 52°.

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What is the area of a parallelogram whose vertices are A(−12, 2) , B(6, 2) , C(−2, −3) , and D(−20, −3) ? Enter your answer in t

nikdorinn [45]

Let

$A(-12,2)\\B(6,2)\\C(-2,-3) \\D(-20.-3)\\E(-12.-3)$

using a graphing tool

see the attached figure to better understand the problem

we know that

Parallelogram is a quadrilateral with opposite sides parallel and equal in length

$AB=CD \\AD=BC$

The area of a parallelogram is equal to

$A=B*h$

where

B is the base

h is the height

the base B is equal to the distance AB

the height h is equal to the distance AE

Step 1

Find the distance AB

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

$A(-12,2)\\B(6,2)$

substitute the values

$d=\sqrt{(2-2)^{2}+(6+12)^{2}}$

$d=\sqrt{(0)^{2}+(18)^{2}}$

$dAB=18\ units$

Step 2

Find the distance AE

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

$A(-12,2)\\E(-12.-3)$

substitute the values

$d=\sqrt{(-3-2)^{2}+(-12+12)^{2}}$

$d=\sqrt{(-5)^{2}+(0)^{2}}$

$dAE=5\ units$

Step 3

Find the area of the parallelogram

The area of a parallelogram is equal to

$A=B*h$

$A=AB*AE$

substitute the values

$A=18*5=90\ units^{2}$

therefore

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the area of the parallelogram is $90\ units^{2}$

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Answer:

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Step-by-step explanation:

To find this, start by finding t(-7)

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t(-7) = -21

Now that we have this answer, we input it into the s(x) equation.

s(x) = 2 - x^2

s(-21) = 2 - (-21)^2

s(-21) = 2 - 441

s(-21) = -439

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Come help a sister out on 2 geometry questions please

PSYCHO15rus [73]

1- question

Data:
width = 6 cm
length = 5 cm
height = 8 cm

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Ab = 6 * 5
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Solving:
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$\boxed{\boxed{V = 80\:cm^3}}\end{array}}\qquad\quad\checkmark$

Answer:
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2- question:

Data:
width = 7 in
length = 7 in
height = 9 in

First we will find the area of the base that is square, we have:

Ab = 7 * 7
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Now we will calculate the volume of a square pyramid, we have:
Formula: $V = \frac{1}{3} A_{b} *h$

Solving:
$V = \frac{1}{3} A_{b} *h$
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Answer:
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