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GuDViN [60]
2 years ago
6

12th grade stat and prob !!!!

Mathematics
1 answer:
aliya0001 [1]2 years ago
5 0

Answer:

The 1st one .

Step-by-step explanation:

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please help me answer this question Solve: y − x = 12 y + x = -26 (19, -7). (-7, 1). (7, 19). (-19, -7).
Tpy6a [65]

Answer:

(-19 , -7)

Step-by-step explanation:

y - x = 12

y + x = -25 we sum them to get

2y = -14 , y = -7

then we put -7 instead of y in any of the equations:

-7 - x = 12

-x = 19

x = -19,

finally (x , y) is (-19 , -7)

3 0
3 years ago
Calculus Problem
Roman55 [17]

The two parabolas intersect for

8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2

and so the base of each solid is the set

B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, |x^2-(8-x^2)| = 2|x^2-4|. But since -2 ≤ x ≤ 2, this reduces to 2(x^2-4).

a. Square cross sections will contribute a volume of

\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x

where ∆x is the thickness of the section. Then the volume would be

\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x

We end up with the same integral as before except for the leading constant:

\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx

Using the result of part (a), the volume is

\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x

and using the result of part (a) again, the volume is

\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}

7 0
2 years ago
What is an isometry that maps all points of a figure the same distance in the same direction.
stira [4]
 A translation
(I'm assuming that this isn't multiple choice since you didn't include the answer choices.)
4 0
3 years ago
Sam is 5 years older than Mike. In 6 years, Mike will be 7 more than half of Sam's age. How old is Sam now?
9966 [12]
The Correct answer is B.18
5 0
2 years ago
Four friends share 5 pizzas equally, how much pizza did each friend get?
yarga [219]

Answer:

1 1/4 or 5/4

Step-by-step explanation:

Divide 5 by 4

5 0
3 years ago
Read 2 more answers
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