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Ivahew [28]
3 years ago
13

Suppose the line of best fit is being found for some data points that have an r-value of 0.793. If the standard deviation of the

x-coordinates is 5.591, and the standard deviation of the y-coordinates is 2.772, what is the slope of the line to three decimal places?
Mathematics
1 answer:
alexandr1967 [171]3 years ago
6 0
Answer: 0.393

Explanation: If the given quantities are r-value (or Pearson's coefficient) and the standard deviations of x and y coordinates, we'll use the following formula for slope:

m =  \frac{rs_y}{s_x} 



where:
m = slope of the best fit line
r = r-value = 0.793
s_x = standard deviation of x-coordinates = <span>5.591
</span>s_y = standard deviation of y-coordinates = 2.772

So, the slope is calculated as follows:

m = \frac{rs_y}{s_x}&#10;\\ = \frac{(0.793)(2.772)}{5.591}&#10;\\ \boxed{m \approx 0.393}

Hence, the slope in 3 decimal places is 0.393.
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