Answer:
61.0168 g/mol Explanation:
Answer:
Explanation:
Given that,
Hot reservoir temperature is
TH = 58°C
TH = 58 + 273 = 331 K
Cold reservoir temperature
TC = -17°C
TC = -17°C + 273 = 256K
In 24minutes 590 J of heat was removed from hot reservoir
t = 24mins
t = 24 × 60 = 1440 seconds
Then,
Power is given as
P = E / t
P = 590 / 1440
P = 0.41 W
Since this removed from the hot reservoir, then, QH = 0.41W
We want to find heat expelled to the cold reservoir QX
Efficiency is given as
η = 1 - TH/TC = 1 - QH/QC
1 - TH/TC = 1 - QH/QC
TH/TC = QH/QC
Make QC subject of formula
QC = QH × TC / TH
QC = 0.41 × 256 / 331
QC = 0.317 W
In an uniformly accelerated motion, the velocity of the object follows the law:
where
is the initial velocity, a the acceleration and t the time.
In our problem, the robot starts from rest, so the initial speed is zero:
. The robot is in free fall, so the acceleraion is the gravitational acceleration
. therefore, after a time
, the velocity is
Answer:
a) 14.2sec
b) 1394m away if horizontal speed never changes
c) 9.8m/s
Explanation:
Answer:
Scalar quantities are physical quantities which have a magnitude and direction.
e.g. in 5 km, 5 is the magnitude(number) and km is the unit.
some scalar quantities are mass, length, distance, speed, power, energy, temperature etc.
