516.154 megawatts of heat are <em>exhausted</em> to the river that cools the plant.
By definition of energy efficiency, we derive an expression for the energy rate exhausted to the river (
), in megawatts:
(1)
Where:
- Efficiency.
- Electric power, in megawatts.
If we know that
and
, then the energy rate exhausted to the river is:


516.154 megawatts of heat are <em>exhausted</em> to the river that cools the plant.
We kindly to check this question on first law of thermodynamics: brainly.com/question/3808473
Answer: 1. 0.25 m/s squared
2. A = 0.4 m/s^2
3.=20kg. I did this before.
Explanation:
Answer:
5.78amps
Explanation:
Given data
Time t= 57 seconds
Charge Q= 330C
Current I= ??
The expression for the electric current is given as
Q= It
Substituting we have
330= I*57
I= 330/57
I=5.78 amps
Hence the current is 5.78amps