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zloy xaker [14]
3 years ago
5

A museum sets up a display of fluorescent minerals. Which best describes how electromagnetic waves can be used to enhance the di

splay?
Infrared light shining on the minerals will cause them to give off visible light.
Visible light shining on the minerals will cause them to give off infrared light.
Ultraviolet light shining on the minerals will cause them to give off visible light.
Visible light shining on the minerals will cause them to give off ultraviolet light.
Physics
1 answer:
Volgvan3 years ago
4 0

Answer:c

Explanation:

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In this exercise we have to know the definition of energy to understand what is transferred to a body, like this:

Work

<h2>What is energy?</h2>

Despite being used in many different contexts, the scientific use of the word energy has a well-defined and precise meaning: Innate potential to perform work or perform an action. Anything that is working, moving another object, or heating it up, for example, is expending (transferring) energy.

With this definition we can say that the only alternative that responds to this is work.

See more about energy at brainly.com/question/1932868

6 0
2 years ago
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Answer the question fast please​
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Answer:

1

Explanation:

d = m \div v  \\ m = 0.8 \: v = 80\% \: also \: 0.8 \\ d = 0.8 \div 0.8 \\ d = 1

6 0
3 years ago
A student sees a commercial that claims a new dishwasher is energy efficient.
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Answer:

ENERGY STAR-certified dishwashers

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8 0
3 years ago
What type of energy does an object gain as it is lifted at a constant speed?
marshall27 [118]
D. Gravitational potential
7 0
3 years ago
Proposed Exercise - Circular Movement
notka56 [123]

Answer:

ωB = 300 rad/s

ωC = 600 rad/s

Explanation:

The linear velocity of the belt is the same at pulley A as it is at pulley D.

vA = vD

ωA rA = ωD rD

ωD = (rA / rD) ωA

Pulley B has the same angular velocity as pulley D.

ωB = ωD

The linear velocity of the belt is the same at pulley B as it is at pulley C.

vB = vC

ωB rB = ωC rC

ωC = (rB / rC) ωB

Given:

ω₀A = 40 rad/s

αA = 20 rad/s²

t = 3 s

Find: ωA

ω = αt + ω₀

ωA = (20 rad/s²) (3 s) + 40 rad/s

ωA = 100 rad/s

ωD = (rA / rD) ωA = (75 mm / 25 mm) (100 rad/s) = 300 rad/s

ωB = ωD = 300 rad/s

ωC = (rB / rC) ωB = (100 mm / 50 mm) (300 rad/s) = 600 rad/s

5 0
2 years ago
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