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Arte-miy333 [17]
2 years ago
7

Each incomplete reaction is a neutralization reaction. Match each equation with the salt formed.

Chemistry
2 answers:
ddd [48]2 years ago
6 0
Based on the incomplete neutralization reaction above, the corresponding salts that each reaction would form are as follows:
1. H2SO4 + 2NH4OH----(NH4)2SO4 with water as a byproduct
2. 2NaOH + H2CO3 ----Na2CO3 with water as a byproduct
3. HNO3 + KOH ----KNO3 with water as a byproduct
Serggg [28]2 years ago
6 0

Explanation:

Neutralization reaction Is chemical reaction between acid and base which gives water and salt as product.

2H_2SO_4+2NH4OH\rightarrow 2(NH_4)_2SO_4+3H_2O

The salt formed in reaction will be (NH_4)_2SO_4.

2NaOH+H_2CO_3\rightarrow Na_2CO_3+2H_2O

The salt formed in reaction will beNa_2CO_3

HNO_3+KOH\rightarrow KNO_3+H_2O

The salt formed in reaction will beKNO_3.

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Please solve for Cu,N,and O an dif you can show how cause ik confused
belka [17]

Cu⇒ 1 atom

N⇒2 atoms

O⇒6 atoms

Total 9 atoms

<h3>Further explanation  </h3>

The empirical formula is the smallest comparison of atoms of compound forming elements.  

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

<em>(empirical formula) n = molecular formula  </em>

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Number of Cu : 1

Number of N : 2

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Total atoms in Cu(NO₃)₂ : 1 + 2 + 6 = 9

4 0
2 years ago
The half-life of a first-order reaction is 13 min. If the initial concentration of reactant is 0.085 M, how long would it take u
olasank [31]

Answer: It will take 8.2 minutes until the concentration decreases to 0.055 M

Explanation:

The time after which 99.9% reactions gets completed is 40 minutes

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant

a - x = amount left after decay process  

a) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.693}{13min}=0.053min^{-1}

b)  Time taken for 0.085 M to decrease to 0.055 M

t=\frac{2.303}{0.053}\log\frac{0.085}{0.055}

t=8.2min

Thus it will take 8.2 minutes until the concentration decreases to 0.055 M

5 0
3 years ago
6832 J of heat energy is applied to 5.9 mol of water. If the original temperature of the water was 18.60C, the final temperature
sineoko [7]

Answer: The final temperature of the water will be 34.0^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed=6832 Joules

m= mass of water = 5.9mol\times 18g/mol=106.2g

c = specific heat capacity = 4.184J/g^0C

Initial temperature of the water = T_i = 18.6^0C

Final temperature of the water = T_f  = ?

Putting in the values, we get:

6832=106.2\times 4.184\times (T_f-18.6)

T_f=34.0^0C

The final temperature of the water will be 34.0^0C

8 0
3 years ago
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3 0
3 years ago
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