Answer:
True
Explanation:
This means the fuel is highly flammable hence it has a low ignition temperature. This, therefore, means it burns fast without putting in a lot of energy to ignite it. Even in cars, therefore, the compression ratios, in engines using these of these fuels, is lesser.
Answer:
53.1 mL
Explanation:
Let's assume an ideal gas, and at the Standard Temperature and Pressure are equal to 273 K and 101.325 kPa.
For the ideal gas law:
P1*V1/T1 = P2*V2/T2
Where P is the pressure, V is the volume, T is temperature, 1 is the initial state and 2 the final state.
At the eudiometer, there is a mixture between the gas and the water vapor, thus, the total pressure is the sum of the partial pressure of the components. The pressure of the gas is:
P1 = 92.5 - 2.8 = 89.7 kPa
T1 = 23°C + 273 = 296 K
89.7*65/296 = 101.325*V2/273
101.325V2 = 5377.45
V2 = 53.1 mL
Answer is <span>
Ni²</span>⁺(aq)
+ 6NH₃(aq)
⇌ [Ni(NH₃)₆]²⁺<span>
</span>
<span>When the concentration of Ni²⁺</span><span>(aq) increases, according to the Le Chatelier’s principle
system tries to become equilibrium by reducing the increased factor. To do
that, the concentration of Ni²⁺</span><span>(aq) should be reduced. Hence, the forward reacted should be
promoted to reduce the Ni²⁺</span><span>(aq) concentration</span>.
Gas and radio waves I’m pretty sure is correct
<span>200 moles
The balanced equation for creating water from hydrogen and oxygen gas is
2H2 + O2 => 2H2O
So for every mole of oxygen gas, you need two moles of hydrogen. So looking that the amount of oxygen and hydrogen you have, it's obvious that oxygen is the limiting reactant since 100 moles of oxygen will consume 200 moles of hydrogen. While 210 moles of hydrogen requires 105 moles of oxygen.
Now for each mole of oxygen gas you use, you create 2 moles of water. So
100 mol * 2 = 200 mol
So you can create 200 moles of water from the given amounts of reactants.</span>
