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Agata [3.3K]
3 years ago
9

2Na+2HCI-H,+2Naci

Chemistry
1 answer:
White raven [17]3 years ago
5 0

Answer:

Single Replacement reaction

Explanation:

Reaction Given:

            2Na + 2HCI ------> H₂ + 2NaCl

Type of reaction = ?

Solution:

Look at the reactants and products of the reaction to know the type of reaction

           2Na + 2HCI ------> H₂ + 2NaCl

In this reaction two reactant combine and give 2 products.

Reactant of the reaction

Na = Sodium

HCl = Hydrochloric acid

Product of the reaction

NaCl = sodium chloride

H₂ = hydrogen gas

So,

That sodium metal react with hydrochloric acid and produce salt and water gas

Type of Reaction:

This is a Single Replacement reaction, in which Sodium metal (Na) replace the Hydrogen (H) of the other compound and form Sodium Chloride salt (NaCl)  and hydrogen liberate in the form of gas.

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Can I get help with this, please!!
kondor19780726 [428]

Pressure in the submarine when the temperature is changed to 293 K is 108.9 K Pa

Explanation:

Pressure in the submarine = 108.9 kPa

Volume, V = 2.4 * 10^5 L

Pressure, P = 116k Pa

Temperature, T = 312 K

Ideal gas law: PV = nRT  or  n = PV / RT

So, moles of gas, n =116 KPa * 2.4 * 10 ^5L / 8.314 LK Pa K^-1 *312 K

= 1.073 *10^4 mol

when temperature is changed to 293K,

PV = nRT  or P = nRT / V

=1.073 *10^4 mol *8.314 LK Pa mol^-1 K^-1 *293 K / 2.4*10^5L

=108.9 K Pa

Pressure in the submarine when the temperature is changed to 293 K is 108.9 K Pa

8 0
3 years ago
For the following electrochemical reaction: Al3+(aq) + 3e -> Al(s) Eº = -1.66 V E° = 2.87 F2(g) + 2e -> 2F (aq) Calculate
makvit [3.9K]

<u>Answer:</u> The standard electrode potential of the cell is 4.53 V.

<u>Explanation:</u>

We are given:

E^o_{(F_2/F^-)}=2.87V\\E^o_{(Al^{3+}/Al)}=-1.66V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Aluminium will undergo oxidation reaction and will get oxidized.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=2.87-(-1.66)=4.53V

Hence, the standard electrode potential of the cell is 4.53 V.

6 0
3 years ago
What is the molarity of a solution that has 4.4 moles BaCl2 in 1.5 Liters of solution?
garik1379 [7]

Answer:

2.9 M

Explanation:

Step 1: Given data

Moles of barium chloride (solute): 4.4 moles

Volume of solution: 1.5 liters

Step 2: Calculate the molarity of barium chloride in the solution

The molarity is a way to quantitatively express the concentration of a solute in a solution. The molarity is equal to the moles of solute divided by the volume, in liters, of solution.

M=\frac{4.4mol}{1.5L} =2.9 M

7 0
3 years ago
ddt, dde, pcbs and pbdes are all ________ddt, dde, pcbs and pbdes are all ________.a biodegradable and do not persist in the env
qwelly [4]
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5 0
3 years ago
What is defined as the basic unit in the metric system that describes a quality
Bingel [31]

Answer:

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Time - second (s)

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Electric current - ampere (A)

Temperature - kelvin (K)

Luminous intensity - candela (cd)

Mass - kilogram (kg)

3 0
3 years ago
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