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nika2105 [10]
3 years ago
9

Triangle ABC is translated 2 units right and 5 units down to form triangle A'B'C'. This triangle is then translated 5 units righ

t a
form triangle A"B"C". If vertex A is at (-4,2), what are the coordinates of vertex A"?
A (3,-1)
B. (3,1)
C(-4,-2)
D. (2.-4)
E. (-11, 1)
Mathematics
1 answer:
Leno4ka [110]3 years ago
3 0

Answer:

The answer is choice A, a.k.a. (3,1)

Step-by-step explanation:

It is given that triangle ABC is translated 2 units right and 5 units down to form triangle A′B′C′. It means  triangle A'B'C' is translated 5 units right and 4 units up to form triangle A″B″C″.  

Therefore the coordinates of vertex A″ are (3,1).

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Which of the following is a Type I​ error?
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C. The president rejects the hypothesis that the proportion of students who earn a​ bachelor's degree within six years is 0.398​, ​when, in​ fact, the proportion is 0.398.

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3 years ago
Using suitable identity evaluate the following : 98^3
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941,192

Steps:

(a-b)^3=a^3-b^3-3a^2b+3ab

\begin{gathered} (98)^3=(100-2)^3 \\ (100-2)^{3\text{ }}=(100)^3-(2)^3-3\cdot(100)^2\cdot2+3\cdot100\cdot2^2\text{ } \\ (100)^3-(2)^3-3\cdot(100)^2\cdot2+3\cdot100\cdot2^2\text{ = 1,0}00,000\text{ - 3 - 60,000 +1,200} \\ \text{ 1,0}00,000\text{ - 3 - 60,000 +1,200 = 941,192} \end{gathered}

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1 year ago
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