Easy
ok, so
for y=a(x-h)^2+k
the vertex is (h,k)
given that the the vertex is (-2,-20)
y=a(x-(-2))^2+(-20)
y=a(x+2)^2-20
find a
when x=0, then y=-12
-12=a(0+2)^2-20
-12=a(2)^2-20
8=4a
2=a
equation is
y=2(x+2)^2-20
if the last term is positive, then maybe y=2(x+2)^2+(-20)?
unless you typed something wrong, then you are right that the last term is -20
Answer:
Diego
Step-by-step explanation:
divide 132 minutes by 44 pages and you get 3 pages per minute, then divide 140 minutes by 35 pages and you will get 4 pages per minute. so Diego reads 1 more page a minute than lin. hope i helped you :)
Answer:
1/4?
Step-by-step explanation:
50. since n_1/4<1 the equation is not true. it has no solution.
48. same thing since 45 <= z the equation is not true.
What questions? Idk where the pic is
