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finlep [7]
3 years ago
6

Suppose you have 3 pieces of string measuring 6 inches, 9 inches, and 12 inches. How many unique triangles can you form with the

se pieces of string?
Mathematics
1 answer:
siniylev [52]3 years ago
8 0
A triangle should have 3 points and 3 sides. Let say that the point is ABC. Then the sides would be AB, AC and BC.
There are 3 strings with a different length that can be put into the sides. Assuming the string can be used once, then the possible way would be:
3!/(1+3-3)!= 3!/1!= 3*2*1= 6 ways
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Rational expression. simplify<br> 36m-48m over 6m.
ladessa [460]
One way is to find common factors

example

8/6=4/3 because 8/6, 8 and 6 have common factor of 2 so divide that out to get 4/3
basically divide the LCM from each

so factor

we can combine 36m-48m into -12m
we have
-12m/6m

common factor is 6m
-12m/6m=(-2)/1 times (6m)/(6m)=-2 times 1=-2

answer is -2
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3 years ago
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5. (Total 16 points)
Mila [183]
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3 years ago
Sole m-2/12=1/6<br> a.4<br> b.1<br> c.0<br> d.2
riadik2000 [5.3K]
The answer would be A. 4
Here’s what I would do.
Multiply both sides by 12 so u can get m- 2 by itself.
m-2= 2
How’d I get the two? It comes from when I multiplied 12 on both sides. 12/6= 2
Now ur equation should be
m-2=2
Do the opposite and add two to both sides to get the variable by itself.
m=4

Hope this helps :)))
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A BOWL HAS SLIPS OF PAPER WITH A SINGLE NUMBER ON IT WITH NUMBERS FROM 2 TO 13. NO NUMBER IS REPEATED. WHAT ARE THE ODDS AGAINST
iren2701 [21]

you have a 58%(rounded) chance against picking a prime number at random

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