A triangle should have 3 points and 3 sides. Let say that the point is ABC. Then the sides would be AB, AC and BC. There are 3 strings with a different length that can be put into the sides. Assuming the string can be used once, then the possible way would be: 3!/(1+3-3)!= 3!/1!= 3*2*1= 6 ways
Well the first thing you have to do is find out how many times 7 goes into 50 whole. This is 7. So then you take the answer to (7x7) from 50 which gives you one, and put it over 50. This equals 7 + 1/50