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Anon25 [30]
3 years ago
9

I need help with this problem its 620÷20 and 600÷100

Mathematics
2 answers:
dusya [7]3 years ago
8 0
620/20=31

600/100=6

Those are my answers. :)

Hope it helps! :D
dybincka [34]3 years ago
5 0
31 for 620/20 and 6 for 600/100
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I don’t understand this at all
Lemur [1.5K]

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Answer:

  9(x +y)

Step-by-step explanation:

You observe that both terms have a coefficient of 9. The distributive property lets you factor that out, so you can rewrite the expression as ...

  9x +9y = 9(x +y)

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It might help to think of parentheses as a "bag." The expression 9(x+y) tells you the contents of one bag is (x+y) and you have 9 of them. You could think of x, and y as representing two different physical objects, for example, perhaps a ball and a cube.

The first expression, 9x +9y, tells you that you have 9 of each of these objects. The distributive property says this could be the result of dumping the contents of 9 bags, each containing one each of the objects. The expression 9(x+y) is the version of the expression that shows these objects as being grouped into 9 bags.

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lisabon 2012 [21]

Answer:

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Step-by-step explanation:

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8 0
2 years ago
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Which is greater than 4?<br><br>(a) 5,<br>(b) -5,<br>(c) -1/2,<br>(d) -25.
Archy [21]
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5 0
3 years ago
Solve this equation. 34 + x = 63
Katena32 [7]
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I need help I can’t figure it out
dusya [7]

Answer:

\large\boxed{\dfrac{41p}{70q^4(r-9)^2}}

Step-by-step explanation:

\dfrac{2p^4}{5q^5(r-9)^3}\cdot\dfrac{41q(r-9)}{28p^3}\\\\=\dfrac{2\!\!\!\!\diagup^1\cdot41}{5\cdot28\!\!\!\!\!\diagup_{14}}\cdot\dfrac{q\!\!\!\!\diagup}{q^{5\!\!\!\!\diagup^4}}\cdot\dfrac{(r\!\!\!\!\!\!{--}-9)\!\!\!\!\!\!{--}}{(r-9)^{3\!\!\!\!\diagup^2}}\cdot\dfrac{p^{4\!\!\!\!\diagup}}{p^3\!\!\!\!\!\!\diagup}\\\\=\dfrac{41}{70}\cdot\dfrac{1}{q^4}\cdot\dfrac{1}{(r-9)^2}\cdot\dfrac{p}{1}\\\\=\dfrac{41p}{70q^4(r-9)^2}

7 0
3 years ago
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