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Nata [24]
3 years ago
5

Sole m-2/12=1/6 a.4 b.1 c.0 d.2

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
7 0
The answer would be A. 4
Here’s what I would do.
Multiply both sides by 12 so u can get m- 2 by itself.
m-2= 2
How’d I get the two? It comes from when I multiplied 12 on both sides. 12/6= 2
Now ur equation should be
m-2=2
Do the opposite and add two to both sides to get the variable by itself.
m=4

Hope this helps :)))
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How many zeros are in the product (6•5)•10
ASHA 777 [7]
There are 2 zeros in the product.
6*5=30
30*10=300
2 zeros
6 0
3 years ago
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write a real-world problem in which you would need to find the number of units between -6 and 0 on a number line.
Mariulka [41]
Sam started with 0 dollars in his bank account. He charged his debit card for a sandwich that costs $6.00. If this was written on a number line. How many units would Sam to go to get back to where he started?
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4 years ago
(Will give Brainliest & Many Many Points <3 Please help quickly!)
Dmitry_Shevchenko [17]

Answer:

D] f(n) = f(n − 1) + (−7)

Step-by-step explanation:

since you already know is an arithmetic series, you have to find the common difference.

87 - 94 = -7

80 - 87 = -7

73 - 80 = -7

the formula for the nth term is f(n) = f(n-1) + d

where f(n-1) is the previous term and d is the common difference, so if youu substitute you get:

f(n) = f(n-1) + d

f(n) = f(n-1) + (-7)

4 0
4 years ago
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Any help would be great.
Ket [755]

<u>Answer:</u>

log7

<u>Step-by-step explanation:</u>

We are given the following expression in terms of log and we are to solve it:

log (14/3) + log (11/5) - log (22/15)

Just to recall, when we divide two values that have the same base, we basically subtract the exponents.

So applying this rule here to get:

(log11 - log5) + (log14 - log3) - (log22 - log15)

= log11 - log5 + log14 - log3 - log2×11 + log5.3

= loh11 - log5 + log14 - log3 - log2 - log11 + log5 + log3

Cancelling out the like terms to get:

= log14 - log2

= log 14/2

= log7

8 0
4 years ago
A football stadium sells regular and box seating. There are twelve times as many
Vera_Pavlovna [14]

Answer:

There are 801 box seats and 9612 regular seats.

explanation:

Let the number of box seats be x,

Then the regular seats is 12x

The sum of seats equals to 10,413

<u>Solve:</u>

12x + x ➙ 10,413

13x ➙ 10413

x ➙ 801

There are 801 box seats.

<u>Find for regular seats:</u>

➙ 12(x)

➙ 12(801)

➙ 9612

There are 9612 regular seats.

6 0
2 years ago
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