Chelsea wrote several equations and determined that only one of the equations has exactly one solution. Which of these equations
2 answers:
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Answer:
yes, he was effectively a .400 hitter
Step-by-step explanation:
The mean rate of success ( ÿ ) is 0.394.
The total number of hits was 419.
Under table t the value at 5% confidence interval is 1.96.
Here <em>se</em> the asymptotic standard deviation is given as follows
<em>se</em> =
=
= 0.02387
The confidence interval is calculated as follows:
y ± 1.96 * se
0.394 ± 1.96 * 0.02387
the answer is -0.347 or 0.4407)
meaning that the mean lies between -0.347 to 0.4407.
There is strong evidence that 0.4 lies between the above confidence interval.
This means that Gwynn was effectively a 0.4 hitter