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fredd [130]
3 years ago
5

Chelsea wrote several equations and determined that only one of the equations has exactly one solution. Which of these equations

has exactly one solution?
4 (x + 3) = 7 x minus 6
4 (x + 3) + 8 = 4 x + 20
4 (x + 3) + 3 x + 7 x + 12
4 (x + 3) + 6 = 4 x + 9
Mathematics
2 answers:
Olegator [25]3 years ago
8 0

Answer:

It's A

Step-by-step explanation:

I got it right on edge

Tom [10]3 years ago
7 0

Answer:

c

Step-by-step explanation:

I think

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What is the value of this expression?<br><br> ​ 1.5(−2.4+(−5.3))
Ahat [919]

Answer:

-11.55

Step-by-step explanation:

(to get the numbers out of the brackets you have to multiply all the numbers in the brackets to the number that is there, and in this case its 1.5)

1.5x(-2.4)= -3.6

1.5×(-5.3)= -7.95

after that, you add them (because there is a plus sign, not a minus, multiplication sign or a division sign.)

-7.95+ -3.6= -11.55

answer= -11.55

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mixer [17]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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5 0
3 years ago
Find \tan\left(\frac{17\pi}{12}\right)tan( 12 17π ​ )tangent, left parenthesis, start fraction, 17, pi, divided by, 12, end frac
uranmaximum [27]

One way to do this is to notice

\dfrac{17\pi}{12}=\dfrac\pi6+\dfrac{5\pi}4

Then

\tan\dfrac{17\pi}{12}=\tan\left(\dfrac\pi6+\dfrac{5\pi}4\right)=\dfrac{\tan\frac\pi6+\tan\frac{5\pi}4}{1-\tan\frac\pi6\tan\frac{5\pi}4}

We have

\tan\dfrac\pi6=\dfrac{\sin\frac\pi6}{\cos\frac\pi6}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}

and since \tan x has a period of \pi,

\tan\dfrac{5\pi}4=\tan\left(\pi+\dfrac\pi4\right)=\tan\dfrac\pi4=1

and so

\tan\dfrac{17\pi}{12}=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3

7 0
3 years ago
Which of the following best describes the solutions to the inequality shown below?
ollegr [7]
D. I think because you would get a negative
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3 years ago
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